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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)
Correct answer is '940'. Can you explain this answer?
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of...
Given:
- Power, P = 50 kW
- Voltage, V = 440 V
- Frequency, f = 50 Hz
- Number of poles, p = 6
- Full load slip, S = 6%
- Friction and windage losses, P_fw = 300 W
- Core losses, P_core = 600 W
Formula:
The synchronous speed (Ns) of an induction motor is given by the formula:
Ns = (120 * f) / p
The actual speed (N) of an induction motor is given by the formula:
N = (1 - S) * Ns
The power delivered to the motor shaft (P_shaft) is given by the formula:
P_shaft = P - P_fw - P_core
Calculations:
1. Synchronous Speed:
Ns = (120 * 50) / 6 = 1000 rpm
2. Actual Speed:
N = (1 - 0.06) * 1000 = 940 rpm
Explanation:
- The synchronous speed of an induction motor is the speed at which the rotating magnetic field of the stator rotates. It depends on the frequency of the power supply and the number of poles in the motor.
- The actual speed of the motor is lower than the synchronous speed due to slip, which is a measure of how much the rotor speed lags behind the synchronous speed.
- In this case, the full load slip is given as 6%, which means that the rotor speed is 6% lower than the synchronous speed.
- The power delivered to the motor shaft is calculated by subtracting the friction and windage losses and the core losses from the input power. This is the power available for doing useful work.
- The shaft speed at full load is calculated by multiplying the synchronous speed by (1 - S), where S is the slip.
- Therefore, the shaft speed at full load is 940 rpm.
- Power, P = 50 kW
- Voltage, V = 440 V
- Frequency, f = 50 Hz
- Number of poles, p = 6
- Full load slip, S = 6%
- Friction and windage losses, P_fw = 300 W
- Core losses, P_core = 600 W
Formula:
The synchronous speed (Ns) of an induction motor is given by the formula:
Ns = (120 * f) / p
The actual speed (N) of an induction motor is given by the formula:
N = (1 - S) * Ns
The power delivered to the motor shaft (P_shaft) is given by the formula:
P_shaft = P - P_fw - P_core
Calculations:
1. Synchronous Speed:
Ns = (120 * 50) / 6 = 1000 rpm
2. Actual Speed:
N = (1 - 0.06) * 1000 = 940 rpm
Explanation:
- The synchronous speed of an induction motor is the speed at which the rotating magnetic field of the stator rotates. It depends on the frequency of the power supply and the number of poles in the motor.
- The actual speed of the motor is lower than the synchronous speed due to slip, which is a measure of how much the rotor speed lags behind the synchronous speed.
- In this case, the full load slip is given as 6%, which means that the rotor speed is 6% lower than the synchronous speed.
- The power delivered to the motor shaft is calculated by subtracting the friction and windage losses and the core losses from the input power. This is the power available for doing useful work.
- The shaft speed at full load is calculated by multiplying the synchronous speed by (1 - S), where S is the slip.
- Therefore, the shaft speed at full load is 940 rpm.
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Community Answer
A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of...
The synchronous speed of motor is
The Shaft speed is
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?.
A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?.
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?, a detailed solution for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? has been provided alongside types of A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? theory, EduRev gives you an
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