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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)
Correct answer is '940'. Can you explain this answer?
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of...
The synchronous speed of motor is
The Shaft speed is
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of...
To determine the shaft speed of an induction motor at full load, we can use the formula:
Ns = (120 * f) / P
Where:
- Ns is the synchronous speed in RPM
- f is the frequency of the power supply in Hz
- P is the number of poles of the motor
In this case, the motor has a frequency of 50 Hz and 6 poles. Plugging these values into the formula, we can calculate the synchronous speed:
Ns = (120 * 50) / 6 = 1000 RPM
However, the motor operates at a slip, which is the difference between the synchronous speed and the actual speed of the rotor. The slip formula is:
Slip = (Ns - N) / Ns
Where:
- Slip is the slip percentage
- N is the actual speed of the rotor in RPM
We are given that the full load slip is 6%. Rearranging the formula, we get:
N = Ns - (Slip * Ns)
N = 1000 - (0.06 * 1000)
N = 1000 - 60
N = 940 RPM
Therefore, the shaft speed of the motor at full load is 940 RPM.
Ns = (120 * f) / P
Where:
- Ns is the synchronous speed in RPM
- f is the frequency of the power supply in Hz
- P is the number of poles of the motor
In this case, the motor has a frequency of 50 Hz and 6 poles. Plugging these values into the formula, we can calculate the synchronous speed:
Ns = (120 * 50) / 6 = 1000 RPM
However, the motor operates at a slip, which is the difference between the synchronous speed and the actual speed of the rotor. The slip formula is:
Slip = (Ns - N) / Ns
Where:
- Slip is the slip percentage
- N is the actual speed of the rotor in RPM
We are given that the full load slip is 6%. Rearranging the formula, we get:
N = Ns - (Slip * Ns)
N = 1000 - (0.06 * 1000)
N = 1000 - 60
N = 940 RPM
Therefore, the shaft speed of the motor at full load is 940 RPM.
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?.
A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?.
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A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer?, a detailed solution for A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? has been provided alongside types of A 50 kW, 440 V, 50 Hz, 6-pole induction motor has a full load slip of 6%. The friction and windage losses are 300 W, and the core losses are 600 W at full load conditions. What is the shaft speed (in rpm) at full load? (Answer up to the nearest integer)Correct answer is '940'. Can you explain this answer? theory, EduRev gives you an
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