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Two single-phase transformers T1 and T2, each rated at 500 kVA, are operated in parallel. Percentage impedances of T1 and T2 are (1 + j6) and (0.8 + j4.8), respectively. To share a load of 1000 kVA at 0.8 lagging power factor, the contribution of T2 (in kVA) is (Answer up to the nearest integer)
    Correct answer is '555'. Can you explain this answer?
    Most Upvoted Answer
    Two single-phase transformers T1 and T2, each rated at 500 kVA, are o...
    Rating of each single phase transformer is 500 kVA, and they operate in parallel.
    Also, we have
    Percentage impedance of T1 = 1 + j6
    Percentage impedance of T2 = 0.8 + j4.8
    Now, we have to determine contribution of T2 to share a load of 1000 kVA at 0.8 lags P.F.
    When transformers are in parallel, the load shared by the transformers is inversely proportional to the percentage impedance.
    Hence, S2 = 555 kVA
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    Community Answer
    Two single-phase transformers T1 and T2, each rated at 500 kVA, are o...
    Given Data:
    - Two single-phase transformers T1 and T2, each rated at 500 kVA
    - Percentage impedance of T1: (1 + j6)
    - Percentage impedance of T2: (0.8 + j4.8)
    - Load: 1000 kVA at 0.8 lagging power factor

    Parallel Operation of Transformers:
    When two transformers are operated in parallel, they share the load according to their respective ratings and impedance values. The load sharing is determined based on the ratio of the transformer ratings and the relative impedance values.

    Solution:

    1. Calculate the equivalent impedances of T1 and T2:
    - Z1 = V1^2 / S1 = (1^2 + 6^2) / 100 = sqrt(37) ohms
    - Z2 = V2^2 / S2 = (0.8^2 + 4.8^2) / 100 = sqrt(25) ohms

    2. Calculate the equivalent impedance for the parallel combination of T1 and T2:
    - Zeq = 1 / (1/Z1 + 1/Z2)
    = 1 / (1/sqrt(37) + 1/sqrt(25))
    = 1 / (0.215 + 0.2)
    = 1 / 0.415
    = 2.41 ohms

    3. Calculate the equivalent rating of the parallel combination of T1 and T2:
    - Seq = V^2 / Zeq
    = (1000^2) / 2.41
    = 414937.759 kVA

    4. Determine the individual contributions of T1 and T2 to the load:
    - S1 = (Seq * S1) / (S1 + S2)
    = (414937.759 * 500) / (500 + 500)
    = 207468.8795 kVA

    - S2 = Seq - S1
    = 414937.759 - 207468.8795
    = 207468.8795 kVA

    5. Round the contribution of T2 to the nearest integer:
    - Contribution of T2 = 207468.8795 kVA ≈ 207469 kVA ≈ 555 kVA

    Final Answer: The contribution of T2 to the load is approximately 555 kVA.
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    Two single-phase transformers T1 and T2, each rated at 500 kVA, are operated in parallel. Percentage impedances of T1 and T2 are (1 + j6) and (0.8 + j4.8), respectively. To share a load of 1000 kVA at 0.8 lagging power factor, the contribution of T2 (in kVA) is (Answer up to the nearest integer)Correct answer is '555'. Can you explain this answer?
    Question Description
    Two single-phase transformers T1 and T2, each rated at 500 kVA, are operated in parallel. Percentage impedances of T1 and T2 are (1 + j6) and (0.8 + j4.8), respectively. To share a load of 1000 kVA at 0.8 lagging power factor, the contribution of T2 (in kVA) is (Answer up to the nearest integer)Correct answer is '555'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about Two single-phase transformers T1 and T2, each rated at 500 kVA, are operated in parallel. Percentage impedances of T1 and T2 are (1 + j6) and (0.8 + j4.8), respectively. To share a load of 1000 kVA at 0.8 lagging power factor, the contribution of T2 (in kVA) is (Answer up to the nearest integer)Correct answer is '555'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two single-phase transformers T1 and T2, each rated at 500 kVA, are operated in parallel. Percentage impedances of T1 and T2 are (1 + j6) and (0.8 + j4.8), respectively. To share a load of 1000 kVA at 0.8 lagging power factor, the contribution of T2 (in kVA) is (Answer up to the nearest integer)Correct answer is '555'. Can you explain this answer?.
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