Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > A load of 1 KΩ is connected to a diode detec...
Start Learning for Free
A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will be
- a)0.847
- b)0.628
- c)0.734
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A load of 1 KΩ is connected to a diode detector which is shunted by a...
We know,
Given, R = 1kΩ = 1000Ω
C = 10000pF = 10−8F
ωm = 2π × 104rad/sec
On putting these values in (1) we will get,
Free Test
FREE
| Start Free Test |
Community Answer
A load of 1 KΩ is connected to a diode detector which is shunted by a...
Calculation:
1. The maximum permissible depth of modulation can be calculated using the formula:
\(m_{max} = \frac{1}{1 + k^2}\)
2. Given that the load resistance (R) is 1 KΩ, the forward resistance of the diode (r) is 1 Ω, and the modulating signal frequency (fm) is 10 kHz.
3. The reactance of the shunt capacitor (Xc) can be calculated using the formula:
\(Xc = \frac{1}{2πfC}\)
4. Substituting the values of frequency (10 kHz) and capacitance (10 pF) into the formula, we get Xc = 1591.55 Ω.
5. The depth of modulation can be calculated using the formula:
\(m = \frac{Xc}{Xc + r + R}\)
6. Substituting the values of Xc, r, and R into the formula, we get m = 0.847.
Result:
Therefore, the maximum permissible depth of modulation to avoid diagonal clipping with a modulating signal frequency of 10 kHz is 0.847. Hence, the correct answer is option A.
1. The maximum permissible depth of modulation can be calculated using the formula:
\(m_{max} = \frac{1}{1 + k^2}\)
2. Given that the load resistance (R) is 1 KΩ, the forward resistance of the diode (r) is 1 Ω, and the modulating signal frequency (fm) is 10 kHz.
3. The reactance of the shunt capacitor (Xc) can be calculated using the formula:
\(Xc = \frac{1}{2πfC}\)
4. Substituting the values of frequency (10 kHz) and capacitance (10 pF) into the formula, we get Xc = 1591.55 Ω.
5. The depth of modulation can be calculated using the formula:
\(m = \frac{Xc}{Xc + r + R}\)
6. Substituting the values of Xc, r, and R into the formula, we get m = 0.847.
Result:
Therefore, the maximum permissible depth of modulation to avoid diagonal clipping with a modulating signal frequency of 10 kHz is 0.847. Hence, the correct answer is option A.
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer?
Question Description
A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A load of 1 KΩ is connected to a diode detector which is shunted by a 10kpF capacitor. The diode has a forward resistance of 1 Ω. The maximum permissible depth of modulation, so as to avoid diagonal clipping and modulating signal frequency of 10kHz will bea)0.847b)0.628c)0.734d)None of theseCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup