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A single-phase 230 V, 1 kW load is connected across single-phase 230 V, 50 Hz supply through a diode. The power delivered to the load and input power factor respectively are
  • a)
    353.55 W, 0.50
  • b)
    500 W, 0.707
  • c)
    1000 W, 0.707
  • d)
    250 W, 0.50
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A single-phase 230 V, 1 kW load is connected across single-phase 230 ...
Load resistance is
RL = (230)2/1000 Ω
This is a half-rectifier circuit, so rms value of output voltage,
Power absorbed by load resistance
Input power factor
Free Test
Community Answer
A single-phase 230 V, 1 kW load is connected across single-phase 230 ...




Calculation of Power Delivered to the Load and Input Power Factor:




Given Parameters:
- Single-phase 230 V, 1 kW load connected across single-phase 230 V, 50 Hz supply through a diode




Calculation of Power Delivered to the Load:
- Power delivered to the load = 1 kW (given)
- Power factor (for resistive load) = 1
- Therefore, power delivered to the load = 1 kW




Calculation of Input Power Factor:
- Power input = Power delivered to the load = 1 kW
- Voltage = 230 V
- Current flowing through the circuit can be calculated using the formula: P = V x I x cos(θ) where θ is the phase angle between voltage and current
- Since the load is resistive, cos(θ) = 1
- Therefore, current = 1 kW / 230 V = 4.35 A
- Input power factor = cos(θ) = P / (V x I) = 1 / (230 V x 4.35 A) = 0.707




Final Results:
- Power delivered to the load = 1 kW = 1000 W
- Input power factor = 0.707


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A single-phase 230 V, 1 kW load is connected across single-phase 230 V, 50 Hz supply through a diode. The power delivered to the load and input power factor respectively area)353.55 W, 0.50b)500 W, 0.707c)1000 W, 0.707d)250 W, 0.50Correct answer is option 'B'. Can you explain this answer?
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