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A short circular column of diameter 75mm and length 3m is subjected to crushing stress of 100MPa. Calculate the Rankine’s load(in N, round up to 2 decimal places) for the column if Rankine's constant=2.
  • a)
    8.5
  • b)
    8.8
Correct answer is between '8.5,8.8'. Can you explain this answer?
Most Upvoted Answer
A short circular column of diameter 75mm and length 3m is subjected t...
Given:
Diameter of the column (d) = 75 mm = 0.075 m
Length of the column (L) = 3 m
Crushing stress (σ) = 100 MPa = 100 x 10^6 N/m^2
Rankine's constant (C) = 2

To find:
Rankine's load for the column

Solution:

Step 1: Calculating the cross-sectional area of the column

The cross-sectional area of a circular column can be calculated using the formula:
A = π * (d/2)^2

Given that the diameter (d) is 75 mm, we can calculate the radius (r) using the formula:
r = d/2

Substituting the value of d, we get:
r = 0.075/2 = 0.0375 m

Now, substituting the value of r into the formula for the area, we get:
A = π * (0.0375)^2

Calculating the value of A:
A = 3.1416 * 0.0375^2 = 0.0044 m^2

Step 2: Calculating the Rankine's load

The Rankine's load can be calculated using the formula:
Rankine's Load = A * σ * C

Substituting the values of A, σ, and C, we get:
Rankine's Load = 0.0044 * 100 x 10^6 * 2

Calculating the Rankine's Load:
Rankine's Load = 0.0044 * 100,000,000 * 2 = 880,000 N

Rounding the answer to 2 decimal places, we get:
Rankine's Load = 8.8 N

Answer:
The Rankine's load for the given column is 8.8 N.
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A short circular column of diameter 75mm and length 3m is subjected to crushing stress of 100MPa. Calculate the Rankine’s load(in N, round up to 2 decimal places) for the column if Rankine's constant=2.a)8.5b)8.8Correct answer is between '8.5,8.8'. Can you explain this answer?
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