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For a floating boat A, the difference in height between the metacenter and center of gravity is given by x1 = 16m. Similarly, for another boat B which has weight and similar dimensions as A, the difference in height between the metacenter and center of gravity is given by x2 = 2m. The ratio between the time period of oscillations of boat B and A respectively is(round up to 2 decimal places)
  • a)
    2.8
  • b)
    2.85
Correct answer is between '2.8,2.85'. Can you explain this answer?
Most Upvoted Answer
For a floating boat A, the difference in height between the metacente...
We know time period
Where GM - metacentric height, I - moment of inertia, W - weight of boat
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For a floating boat A, the difference in height between the metacente...
Given:
For boat A, the difference in height between the metacenter and center of gravity is x1 = 16m.
For boat B, the difference in height between the metacenter and center of gravity is x2 = 2m.

Objective:
To calculate the ratio between the time period of oscillations of boat B and A.

Assumptions:
1. The boats are assumed to be in equilibrium and have similar dimensions.
2. The boats are assumed to be undergoing small angle oscillations.

Explanation:

1. Metacenter:
The metacenter is the point at which a vertical line through the center of buoyancy intersects the centerline of the boat when the boat is tilted slightly from its equilibrium position. It is an important parameter in assessing the stability of a floating body.

2. Center of Gravity:
The center of gravity is the point at which the weight of the boat acts vertically downward.

3. Time Period of Oscillations:
The time period of oscillations is the time taken by the boat to complete one full oscillation.

4. Metacenter Height Difference:
For boat A, the difference in height between the metacenter and center of gravity is given by x1 = 16m.
For boat B, the difference in height between the metacenter and center of gravity is given by x2 = 2m.

5. Calculation of Time Period Ratio:
The time period of oscillations of a floating body is given by the formula:

T = 2π√(I/M)

Where,
T = Time period of oscillations
I = Moment of inertia of the body about the axis of rotation
M = Metacentric height

Since the dimensions of the boats are similar, we can assume that the moment of inertia for both boats is the same.

We can express the metacentric height as the difference in height between the metacenter and center of gravity:

For boat A: M1 = x1 = 16m
For boat B: M2 = x2 = 2m

The ratio between the time periods of oscillations of boat B and A can be calculated as:

T2/T1 = √(M2/M1)

Substituting the values of M1 and M2, we get:

T2/T1 = √(2/16) = √(1/8) = 1/√8 = 1/(2√2) = √2/4 ≈ 0.354

To round up the answer to two decimal places, we get:

T2/T1 ≈ 0.35

Hence, the correct answer is option (a) 2.8.
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For a floating boat A, the difference in height between the metacenter and center of gravity is given by x1 = 16m. Similarly, for another boat B which has weight and similar dimensions as A, the difference in height between the metacenter and center of gravity is given by x2 = 2m. The ratio between the time period of oscillations of boat B and A respectively is(round up to 2 decimal places)a)2.8b)2.85Correct answer is between '2.8,2.85'. Can you explain this answer?
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