And Aluminium kittle weight 2 kgs holds two litres of water and its he...
Given data:
- Weight of aluminum kettle = 2 kg
- Capacity of kettle = 2 liters
- Power consumed by heater element = 2 kilowatts
- Wastage of heat = 40%
- Initial temperature of water = 20 degrees Celsius
- Specific heat of aluminum = 0.2
Step 1: Calculate the heat required to raise the temperature of water to boiling point
The specific heat formula is given by Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature.
The mass of water can be calculated using the density formula: Density = mass/volume. Since the density of water is 1 kg/liter, the mass of water in the kettle is 2 kg.
The change in temperature is the difference between the boiling point of water (100 degrees Celsius) and the initial temperature (20 degrees Celsius), which is 80 degrees Celsius.
Using the specific heat formula, the heat required to raise the temperature of water to boiling point is Q = (2 kg)(0.2)(80 degrees Celsius) = 32 kilojoules.
Step 2: Calculate the total heat energy supplied by the heater element
The power consumed by the heater element is 2 kilowatts (2000 watts). The time taken to heat the water can be calculated using the formula: Energy = power × time.
Therefore, the total heat energy supplied by the heater element is (2000 watts)(time).
Step 3: Calculate the wastage of heat
Given that 40% of the heat supplied is wasted, the wastage of heat can be calculated as 40% of the total heat energy supplied.
Therefore, the wastage of heat is (0.4)(2000 watts)(time).
Step 4: Calculate the effective heat energy used to raise the temperature
The effective heat energy used to raise the temperature is the total heat energy supplied minus the wastage of heat.
Therefore, the effective heat energy used is (2000 watts)(time) - (0.4)(2000 watts)(time) = (0.6)(2000 watts)(time).
Step 5: Equate the effective heat energy used to the heat required
Since the effective heat energy used is equal to the heat required, we can set up the equation:
(0.6)(2000 watts)(time) = 32 kilojoules
Simplifying the equation, we can calculate the time taken to bring the water to boiling point.
Step 6: Solve for time
Dividing both sides of the equation by (0.6)(2000 watts), we get:
time = (32 kilojoules) / [(0.6)(2000 watts)]
Calculating the value, time is approximately 8.89 seconds.
Therefore, it would take approximately 8.89 seconds to bring the kettle of water to boiling point from an initial temperature of 20 degrees Celsius.
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