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How many separate address and data lines are needed for a memory of 8 K × 16 ?
  • a)
    13 address, 3 data lines
  • b)
    13 address, 16 data lines
  • c)
    12 address, 4 data lines
  • d)
    13 address, 4 data lines
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
How many separate address and data lines are needed for a memory of 8 ...
For a memory of 8 K, we need 13 address lines and 8 data lines.

Explanation:

- 8 K means 8 kilobytes. 1 kilobyte = 1024 bytes. Therefore, 8 K = 8 * 1024 = 8192 bytes.
- To address each byte in the memory, we need a unique address. The number of unique addresses that can be generated with n address lines is 2^n. Therefore, we need 2^13 = 8192 unique addresses to address each byte in the memory.
- Hence, we need 13 address lines to generate these 8192 unique addresses.
- To read or write data from/to the memory, we need a data bus consisting of data lines. Since the memory has a capacity of 8192 bytes, we need 8 data lines to transfer 8 bits of data at a time (1 byte).
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How many separate address and data lines are needed for a memory of 8 ...
Required to address 8K of memory. We know that, 10 address bits allow the addressing of 1024 bytes (1K) of memory.
So, “1024” starts with “10”. Therefore, we need an additional 3 address bits to increase this by a factor of 8 (8 = 2 cubed), giving a total of 13 address bits.
Memory size = 8 K × 16 = 213 × 16
So, address line  = 13, data line = 16
Hence, the correct option is (B).
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