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The above program consists of three concurrent processes and three binary semaphores. The semaphores are initialised as S0 = 1, S1 = 0, S2 = 0. How many times will process P0 print '0'?
  • a)
    Exactly once
  • b)
    Exactly twice
  • c)
    At least twice
  • d)
    Exactly thrice
  • e)
    Exactly four
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The above program consists of three concurrent processes and three bin...
Initially, S0 = 1, S1 = 0 and S2 = 0, so P1 and P2 will wait and P0 will run and make S0 = 0. The wait decrements semaphore by 1 and increments S1 and S2 by 1. So, after P0's 1st run, S1 = 1 and S2 = 1; so '0' is printed. Now, P1 and P2 can run and make S1 = 0 and S2 = 0, but both increment. Therefore, S0 = 1 again. So, P0 again starts and prints '0'. This continues, and '0' is printed at least twice.
Hence, option 3 is the correct answer.
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