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The following program consists of 3 concurrent processes and 3 binary semaphores. The semaphores are initialised as S0 = 1, S1 = 0 and S2 = 0.
How many times will process P0 print '0'?
  • a)
    At least twice
  • b)
    Exactly twice
  • c)
    Exactly thrice
  • d)
    Exactly once
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The following program consists of 3 concurrent processes and 3 binary ...
Initially, S0 = 1, S1 = 0 and S2 = 0.
So, P1 and P2 will wait and P0 will run and make S0 = 0
Wait decrements the semaphore by 1 and Release increments it by 1.
So, after P0's 1st run, S1 = 1 and S2 = 1.
Hence, '0' is printed.
Now, P1 and P2 can run and make S1 = 0 and S2 = 0 but both increment S0 = 1 again.
So, P0 again starts and prints '0'. This continues.
So, '0' will be printed at least twice.
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Community Answer
The following program consists of 3 concurrent processes and 3 binary ...
Initially, S0 = 1, S1 = 0 and S2 = 0.
So, P1 and P2 will wait and P0 will run and make S0 = 0
Wait decrements the semaphore by 1 and Release increments it by 1.
So, after P0's 1st run, S1 = 1 and S2 = 1.
Hence, '0' is printed.
Now, P1 and P2 can run and make S1 = 0 and S2 = 0 but both increment S0 = 1 again.
So, P0 again starts and prints '0'. This continues.
So, '0' will be printed at least twice.
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