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A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?
(Answer up to the nearest integer)
Correct answer is '56'. Can you explain this answer?
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A horizontal flow primary clarifier treats waste water in which 10%, 6...
Solution:
Total percentage of particles removed can be calculated using the following formula:
% Particle Removal = (1 - e^-kX100)
where,
k = constant related to Surface Overflow Rate (SOR)
SOR = 43.2 m3/m2.d
k = (0.0028 x SOR) - 0.0003
k = (0.0028 x 43.2) - 0.0003
k = 0.1191
Now, we need to calculate the effective settling velocity for each particle size:
Effective settling velocity = (settling velocity x removal efficiency)
For particles with settling velocity of 0.1 mm/s:
Effective settling velocity = (0.1 x 0.8) = 0.08 mm/s
For particles with settling velocity of 0.2 mm/s:
Effective settling velocity = (0.2 x 0.9) = 0.18 mm/s
For particles with settling velocity of 1.0 mm/s:
Effective settling velocity = (1.0 x 0.98) = 0.98 mm/s
Now, we can calculate the total percentage of particles removed as follows:
% Particle Removal = (% of particles with settling velocity of 0.08 mm/s x % of particles with settling velocity of 0.18 mm/s x % of particles with settling velocity of 0.98 mm/s) X 100
% Particle Removal = (10 x 60 x 98)/1000 X 100
% Particle Removal = 56%
Therefore, the total percentage of particles removed is 56%.
Total percentage of particles removed can be calculated using the following formula:
% Particle Removal = (1 - e^-kX100)
where,
k = constant related to Surface Overflow Rate (SOR)
SOR = 43.2 m3/m2.d
k = (0.0028 x SOR) - 0.0003
k = (0.0028 x 43.2) - 0.0003
k = 0.1191
Now, we need to calculate the effective settling velocity for each particle size:
Effective settling velocity = (settling velocity x removal efficiency)
For particles with settling velocity of 0.1 mm/s:
Effective settling velocity = (0.1 x 0.8) = 0.08 mm/s
For particles with settling velocity of 0.2 mm/s:
Effective settling velocity = (0.2 x 0.9) = 0.18 mm/s
For particles with settling velocity of 1.0 mm/s:
Effective settling velocity = (1.0 x 0.98) = 0.98 mm/s
Now, we can calculate the total percentage of particles removed as follows:
% Particle Removal = (% of particles with settling velocity of 0.08 mm/s x % of particles with settling velocity of 0.18 mm/s x % of particles with settling velocity of 0.98 mm/s) X 100
% Particle Removal = (10 x 60 x 98)/1000 X 100
% Particle Removal = 56%
Therefore, the total percentage of particles removed is 56%.
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A horizontal flow primary clarifier treats waste water in which 10%, 6...
Surface overflow rate
Settling velocity more than 0.5 mm/s will be removed 100% and rest is proportional to their settling velocity.
∴ Total percentage of particle removal
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A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer?
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A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer?.
A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal flow primary clarifier treats waste water in which 10%, 60% and 30% of particles have settling velocities of 0.1 mm/s, 0.2 mm/s, 0.2 mm/s, and 1.0 mm/s respectively. What would be the total percentage of particles removed if clarifier operates at a Surface Overflow Rate (SOR) of 43.2 m3/m2.d?(Answer up to the nearest integer)Correct answer is '56'. Can you explain this answer?.
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