The magnetic moment of an octahedral Co(II) complex is 4.0 uB. The d-e...
Magnetic Moment of an Octahedral Co(II) Complex
The magnetic moment of an octahedral Co(II) complex is given as 4.0 uB. To determine the d-electron configuration of Co(II), we can use the formula:
μ = √n(n+2) BM
where μ is the magnetic moment in Bohr magnetons (BM), n is the number of unpaired electrons, and BM is the Bohr magneton (9.27 × 10^-24 J/T).
Using the given magnetic moment, we can rearrange the formula to solve for n:
n = (μ/√(n+2)) / BM
n = (4.0/√(n+2)) / 9.27 × 10^-24
n+2 = (4.0 / (n/(9.27 × 10^-24))^2
n+2 = 4.0 / (n/(9.27 × 10^-24))^2
Solving the equation using trial and error, we get n = 3. This means that there are three unpaired electrons in the d-orbitals of Co(II).
D-Electron Configuration of Co(II)
The d-electron configuration of Co(II) can be determined by filling the d-orbitals with electrons according to the Aufbau principle, Hund's rule, and the Pauli exclusion principle.
The electronic configuration of Co(II) is [Ar] 3d7. In an octahedral complex, the d-orbitals split into two sets: t2g (dxy, dyz, dzx) and eg (dx2-y2, dz2) orbitals.
Since there are three unpaired electrons in the d-orbitals of Co(II), they will occupy the t2g orbitals first, followed by the eg orbitals. Therefore, the d-electron configuration of Co(II) in an octahedral complex is:
t2g5 eg2
This is the correct answer (option B) as it corresponds to the observed magnetic moment of 4.0 uB.
The magnetic moment of an octahedral Co(II) complex is 4.0 uB. The d-e...
For 3 unpaired electrons the magnetic moment is 3.8~4. Therefore the correct order of filling electrons is option B.