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The Fourier series expansion of a real periodic signal with fundamental frequency f0 is given by gp(t) = . It is given that C3 = 3 + j5. Then, C-3 is
  • a)
    5 + j3
  • b)
    -3 - j5
  • c)
    -5 + j3
  • d)
    3 - j5
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The Fourier series expansion of a real periodic signal with fundament...
Here, C3 = 3 + j5
For real periodic signal,
C-k = Ck*
Thus, C-3 = 3 - j5
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