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At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:
Correct answer is '5'. Can you explain this answer?
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Most Upvoted Answer
At STP, the volume of nitrogen gas required to cover a sample of sili...
Number of molecules per gram of nitrogen in monolayer
= 
= 3.48 × 1019
Cross-sectional area of a molecule = 1.6 × 10−19m2
∴ Area covered by the molecules per gram = 3.48 × 1019 × 1.6 × 10−19 = 5.568 m2
∴ Surface area = 5.568 m2 g−1
= (1.113 × A) m2 g−1
A = 5
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Community Answer
At STP, the volume of nitrogen gas required to cover a sample of sili...
Number of molecules per gram of nitrogen in monolayer
=
= 3.48 × 1019
Cross-sectional area of a molecule = 1.6 × 10−19m2
∴ Area covered by the molecules per gram = 3.48 × 1019 × 1.6 × 10−19 = 5.568 m2
∴ Surface area = 5.568 m2 g−1
= (1.113 × A) m2 g−1
A = 5
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At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer?
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At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer?.
At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer?.
Solutions for At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer?, a detailed solution for At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? has been provided alongside types of At STP, the volume of nitrogen gas required to cover a sample of silica gel, assuming langmuir monolayer adsorption, is found to be 1.30 cm3 g−1 of the gel. The area occupied by a nitrogen molecule is 0.16 nm2. What is the surface area per gram of silica gel? [Given NA = 6 × 1023]. The area may be 1.113 × A m2 g−1. The value of A is:Correct answer is '5'. Can you explain this answer? theory, EduRev gives you an
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