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Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface  
of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.
(3 x 47.73 )1/3
47t       =2.24.
(2.24)2 = 5
Q.
Surface area of charcoal adsorbed by each molecule of (acetic acid) is —
  • a)
    7.8 x 10-'9 cm2    
  • b)
    7.8 x 10-15 cm2   
  • c)
    7.8 x 10-17 cm2  
  • d)
    7.8 x 10-16 cm2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Adsorption is the presence of excess concentration of any particular c...
Explanation:

Given:
- Adsorption of H2: 1.12 cm3/g of charcoal
- Density of H2: 0.07 g/cm3
- Adsorption of CH3COOH: 100 ml/g of charcoal
- Concentration of CH3COOH: 0.5 M
- Polarity of CH3COOH after adsorption: 0.49(3 x 47.73 )1/347t =2.24
- We need to find the surface area of charcoal adsorbed by each molecule of CH3COOH.

Calculation of the surface area of charcoal adsorbed by each molecule of CH3COOH:

1. Calculation of the number of moles of H2 adsorbed per gram of charcoal:
- Adsorption of H2: 1.12 cm3/g of charcoal
- Density of H2: 0.07 g/cm3
- Volume of H2 adsorbed per gram of charcoal= 1.12 cm3/g of charcoal
- Mass of H2 adsorbed per gram of charcoal= 0.07 g/cm3 x 1.12 cm3/g= 0.0784 g/g of charcoal
- Number of moles of H2 adsorbed per gram of charcoal= Mass of H2 adsorbed per gram of charcoal/Molar mass of H2= 0.0784 g/g of charcoal/ 2 g/mol= 0.0392 mol/g of charcoal

2. Calculation of the number of moles of CH3COOH adsorbed per gram of charcoal:
- Adsorption of CH3COOH: 100 ml/g of charcoal
- Concentration of CH3COOH: 0.5 M
- Volume of CH3COOH adsorbed per gram of charcoal= 100 ml/g of charcoal= 0.1 L/g of charcoal
- Number of moles of CH3COOH adsorbed per gram of charcoal= Concentration of CH3COOH x Volume of CH3COOH adsorbed per gram of charcoal= 0.5 mol/L x 0.1 L/g= 0.05 mol/g of charcoal

3. Calculation of the surface area of charcoal adsorbed by each molecule of CH3COOH:
- Polarity of CH3COOH after adsorption: 0.49(3 x 47.73 )1/347t =2.24
- The Langmuir adsorption isotherm equation is given by:
θ= KaP/(1+KaP)
where θ is the fractional coverage of the surface, P is the pressure of the gas, K is the equilibrium constant, and a is the surface area per molecule.
- For monolayer adsorption, θ=1 and the equation reduces to:
a= 1/KP
- From the given data, we know that the pressure of CH3COOH is 0.5 M and the surface area per molecule can be represented by 'a'.
- Using the Langmuir adsorption isotherm equation, we get:
K= 1/a x 0.5 M
- Substituting the value of K in the equation for surface area, we get:
a= 1/KP= 1/(1/a x 0.5 M x
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Adsorption is the presence of excess concentration of any particular c...
C
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Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer?
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Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer?.
Solutions for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.Surface area of charcoal adsorbed by each molecule of (acetic acid) is a)7.8 x 10-9 cm2b)7.8 x 10-15 cm2c)7.8 x 10-17 cm2d)7.8 x 10-16 cm2Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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