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Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface
of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.
(3 x 47.73 )1/3
47t =2.24.
(2.24)2 = 5
Q.
What is the radius of adsorb hydrogen molecule
- a)2.24 x 10-7 cm
- b)2.24 x 10-5 cm
- c)2.24 x 10-gcm
- d)2.24 x 10-15cm
Correct answer is option 'B'. Can you explain this answer?
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Adsorption is the presence of excess concentration of any particular c...
Solution:
Given,
Volume of hydrogen gas adsorbed, V = 1.12 cm3/g
Density of hydrogen gas, ρ = 0.07 g/cm3
Calculation of monolayer coverage
Monolayer coverage, θ = (V/M) × (1/NA) × (1/σ)
where M is the molar mass of hydrogen gas, NA is Avogadro number, and σ is the surface area per gram of adsorbent.
Molar mass of H2 gas, M = 2 g/mol
Avogadro number, NA = 6.022 × 1023 /mol
Let us assume that the surface area of adsorbent available for adsorption is S in cm2/g. Then, σ = S/g.
Substituting the given values, we get
θ = (1.12/2) × (1/6.022 × 1023) × (1/S) = 9.27 × 10-5/S
Calculation of radius of hydrogen molecule
The radius of hydrogen molecule adsorbed can be determined using the following equation:
r = [(3M/4πNAρθ)]1/3
Substituting the values in the above equation, we get
r = [(3 × 2/4π × 6.022 × 1023 × 0.07 × 9.27 × 10-5/S)]1/3
r = (0.00967/S)1/3
Given that 1 g of charcoal adsorbs 100 ml of 0.5 M CH3COOH to form a monolayer, and the polarity of CH3COOH reduces to 0.49.
Calculation of surface area of adsorbent
The surface area of adsorbent can be determined using the following equation:
SA = (100 × 0.5 × 10-3 × 6.022 × 1023)/(0.49 × 1)
SA = 7.76 × 1020 cm2/g
Substituting the value of S in the equation for r, we get
r = (0.00967/7.76 × 1020)1/3
r = 2.24 × 10-5 cm
Therefore, the radius of adsorbed hydrogen molecule is 2.24 × 10-5 cm.
Given,
Volume of hydrogen gas adsorbed, V = 1.12 cm3/g
Density of hydrogen gas, ρ = 0.07 g/cm3
Calculation of monolayer coverage
Monolayer coverage, θ = (V/M) × (1/NA) × (1/σ)
where M is the molar mass of hydrogen gas, NA is Avogadro number, and σ is the surface area per gram of adsorbent.
Molar mass of H2 gas, M = 2 g/mol
Avogadro number, NA = 6.022 × 1023 /mol
Let us assume that the surface area of adsorbent available for adsorption is S in cm2/g. Then, σ = S/g.
Substituting the given values, we get
θ = (1.12/2) × (1/6.022 × 1023) × (1/S) = 9.27 × 10-5/S
Calculation of radius of hydrogen molecule
The radius of hydrogen molecule adsorbed can be determined using the following equation:
r = [(3M/4πNAρθ)]1/3
Substituting the values in the above equation, we get
r = [(3 × 2/4π × 6.022 × 1023 × 0.07 × 9.27 × 10-5/S)]1/3
r = (0.00967/S)1/3
Given that 1 g of charcoal adsorbs 100 ml of 0.5 M CH3COOH to form a monolayer, and the polarity of CH3COOH reduces to 0.49.
Calculation of surface area of adsorbent
The surface area of adsorbent can be determined using the following equation:
SA = (100 × 0.5 × 10-3 × 6.022 × 1023)/(0.49 × 1)
SA = 7.76 × 1020 cm2/g
Substituting the value of S in the equation for r, we get
r = (0.00967/7.76 × 1020)1/3
r = 2.24 × 10-5 cm
Therefore, the radius of adsorbed hydrogen molecule is 2.24 × 10-5 cm.
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Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer?
Question Description
Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer?.
Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Adsorption is the presence of excess concentration of any particular component at the surface of liquid or solid phase as compared to bulk. This is due to presence of residual forces at the surface of body. In the adsorption of hydrogen gas over a sample, of charcoal, 1.12cm3 of H2(g) measured over S.T.P. was found to adsorb per gram of charcoal. Consider only monolayer adsorption. Density of H2 is 0.07gm/cc. In another experiment same 1 gm charcoal adsorbs 100m1 of 0.5M CH3COOH to form monolayer and thereby the polarity of CH3COOH reduces to 0.49.(3 x 47.73 )1/347t =2.24.(2.24)2 = 5Q.What is the radius of adsorb hydrogen moleculea)2.24 x 10-7 cmb)2.24 x 10-5 cmc)2.24 x 10-gcmd)2.24 x 10-15cmCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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