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To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.
Correct answer is '100'. Can you explain this answer?
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To extend the range of PMMC type ammeter a resistance of 500mΩ is co...
To calculate the new full scale deflection of the PMMC (Permanent Magnet Moving Coil) type ammeter after connecting a shunt resistor, we need to consider the principle of current division and the relationship between the shunt resistance and the meter's internal resistance.
The principle of current division states that the total current entering a junction is divided among the different paths in inverse proportion to their resistances. In this case, the ammeter and the shunt resistor are in parallel, so the total current entering the junction is divided between them.
Let's denote the original full scale deflection of the meter as I_m and the resistance of the shunt resistor as R_shunt. Given that the internal resistance of the meter is 9.5Ω and the shunt resistor is 500mΩ (0.5Ω), we can write the following equation:
I_m = I_total * (R_shunt / (R_shunt + R_meter))
where I_total is the total current entering the junction. Since the ammeter has a full scale deflection of 5A, we can substitute these values into the equation:
5A = I_total * (0.5Ω / (0.5Ω + 9.5Ω))
Simplifying the equation:
5A = I_total * (0.5Ω / 10Ω)
Now, we can solve for I_total:
I_total = 5A * (10Ω / 0.5Ω) = 100A
Therefore, the new full scale deflection of the ammeter after connecting the shunt resistor is 100A.
The principle of current division states that the total current entering a junction is divided among the different paths in inverse proportion to their resistances. In this case, the ammeter and the shunt resistor are in parallel, so the total current entering the junction is divided between them.
Let's denote the original full scale deflection of the meter as I_m and the resistance of the shunt resistor as R_shunt. Given that the internal resistance of the meter is 9.5Ω and the shunt resistor is 500mΩ (0.5Ω), we can write the following equation:
I_m = I_total * (R_shunt / (R_shunt + R_meter))
where I_total is the total current entering the junction. Since the ammeter has a full scale deflection of 5A, we can substitute these values into the equation:
5A = I_total * (0.5Ω / (0.5Ω + 9.5Ω))
Simplifying the equation:
5A = I_total * (0.5Ω / 10Ω)
Now, we can solve for I_total:
I_total = 5A * (10Ω / 0.5Ω) = 100A
Therefore, the new full scale deflection of the ammeter after connecting the shunt resistor is 100A.
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To extend the range of PMMC type ammeter a resistance of 500mΩ is co...
Given
Rsh = 500mΩ = 0.5Ω
Rm = 9.5Ω
Meter full scale deflection, Im = 5 A
For PMMC ammeter,
(where m= Multiplication factor)
(where m= Multiplication factor)∴ m = 20
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To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer?
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To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer?.
To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer?.
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To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer?, a detailed solution for To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? has been provided alongside types of To extend the range of PMMC type ammeter a resistance of 500mΩ is connected in shunt with the meter, internal resistance of meter being 9.5Ω . The original full scale deflection of meter is 5A. After connecting shunt resistor,the new full scale deflection is ______ A.Correct answer is '100'. Can you explain this answer? theory, EduRev gives you an
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