Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >   A boost converter is operated from a source ... Start Learning for Free
A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )
  • a)
    165.35 V
  • b)
    167.50 V
  • c)
    162.57 V
  • d)
    164.83 V
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A boost converter is operated from a source voltage 100 V. The load r...
Given
Vdc = 100 V
r = 0.8 Ω
R = 200 Ω
D = 0.4
Output voltage of boost converter with internal resistance,
Free Test
Community Answer
A boost converter is operated from a source voltage 100 V. The load r...

Given data:
Source voltage = 100 V
Load resistance = 200 Ω
Internal resistance of inductor = 0.8 Ω
Duty cycle (D) = 0.4

Calculation:
1. The average output voltage of a boost converter can be calculated using the formula:
Vo = Vs / (1 - D)

2. Substitute the given values into the formula:
Vo = 100 / (1 - 0.4)
Vo = 100 / 0.6
Vo = 166.67 V

3. However, the internal resistance of the inductor affects the output voltage. The effective load resistance (Reff) is calculated as:
Reff = Load resistance + Internal resistance of inductor
Reff = 200 + 0.8
Reff = 200.8 Ω

4. The average output voltage considering the internal resistance of the inductor is given by:
Vo = Vs * (Reff / (Reff + Load resistance)) / (1 - D)
Vo = 100 * (200.8 / (200.8 + 200)) / (1 - 0.4)
Vo = 100 * (200.8 / 400.8) / 0.6
Vo = 100 * 0.501 / 0.6
Vo = 50.1 / 0.6
Vo = 83.5 V

Final Answer: The average output voltage considering the internal resistance of the inductor is approximately 83.5 V.
Explore Courses for Electrical Engineering (EE) exam

Similar Electrical Engineering (EE) Doubts

Top Courses for Electrical Engineering (EE)

A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer?
Question Description
A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer?.
Solutions for A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A boost converter is operated from a source voltage 100 V. The load resistance is 200Ω . The internal resistance of inductor is 0.8Ω then the average output voltage is ________ V (D=0.4 )a)165.35 Vb)167.50 Vc)162.57 Vd)164.83 VCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev