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Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:
Note: MSB and LSB are not fixed for initial value.
- 8, 12, 14, 7, 15, 3, 1, 0, 8
- 8, 0, 1, 3, 7, 15, 14, 12, 8
- 8, 10, 12, 14, 0, 2, 4, 6, 8
- 8, 12, 14, 15, 7, 3, 1, 0, 8
- a)1
- b)2
- c)3
- d)4
Correct answer is option 'B,D'. Can you explain this answer?
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Most Upvoted Answer
Consider a 4-bit Johnson counter with an initial value of 1000. The co...
Now,
Circuit for Johnson counter:
If Q0 is MSB and Q3 is LSB:
Count sequence of 8 → 12 → 14 → 15 → 7 → 3 → 1 → 0 → 8 → (repeat).
If Q3 is MSB and Q0 is LSB:
If Q3 is MSB and Q0 is LSB:
Count sequence of 8 → 0 → 1 → 3 → 7 → 15 → 14 → 12 → 8 → (repeat).
As we know,
Since the least significant bits and the most significant bit is not signified.
Hence, the correct options are (B) and (D).
Since the least significant bits and the most significant bit is not signified.
Hence, the correct options are (B) and (D).
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Community Answer
Consider a 4-bit Johnson counter with an initial value of 1000. The co...
Introduction:
A Johnson counter is a modified version of a ring counter that generates a sequence of binary numbers. It is a shift register with feedback. In a 4-bit Johnson counter, there are four flip-flops connected in a ring, and the output of each flip-flop is connected to the input of the next flip-flop. The counting sequence of a Johnson counter depends on its initial value.
Given Information:
- A 4-bit Johnson counter
- Initial value: 1000
Counting Sequence:
To determine the counting sequence of the Johnson counter, we need to simulate the counter by manually shifting the values.
Step 1:
Start with the initial value: 1000
Step 2:
Shift the bits to the right, and the leftmost bit becomes the rightmost bit:
1000 -> 0100
Step 3:
Shift the bits to the right again:
0100 -> 0010
Step 4:
Shift the bits to the right once more:
0010 -> 0001
Step 5:
Shift the bits to the right one last time:
0001 -> 1000
Counting Sequence:
The counting sequence of the Johnson counter with an initial value of 1000 is as follows:
- 1000
- 0100
- 0010
- 0001
- 1000
Explanation of Options:
Let's analyze each option and determine if it matches the counting sequence of the Johnson counter.
Option A: 8, 12, 14, 7, 15, 3, 1, 0, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option B: 8, 0, 1, 3, 7, 15, 14, 12, 8
- This sequence matches the counting sequence of the Johnson counter.
Option C: 8, 10, 12, 14, 0, 2, 4, 6, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option D: 8, 12, 14, 15, 7, 3, 1, 0, 8
- This sequence matches the counting sequence of the Johnson counter.
Conclusion:
The counting sequence of the 4-bit Johnson counter with an initial value of 1000 is 8, 0, 1, 3, 7, 15, 14, 12, 8 (Option B) and 8, 12, 14, 15, 7, 3, 1, 0, 8 (Option D).
A Johnson counter is a modified version of a ring counter that generates a sequence of binary numbers. It is a shift register with feedback. In a 4-bit Johnson counter, there are four flip-flops connected in a ring, and the output of each flip-flop is connected to the input of the next flip-flop. The counting sequence of a Johnson counter depends on its initial value.
Given Information:
- A 4-bit Johnson counter
- Initial value: 1000
Counting Sequence:
To determine the counting sequence of the Johnson counter, we need to simulate the counter by manually shifting the values.
Step 1:
Start with the initial value: 1000
Step 2:
Shift the bits to the right, and the leftmost bit becomes the rightmost bit:
1000 -> 0100
Step 3:
Shift the bits to the right again:
0100 -> 0010
Step 4:
Shift the bits to the right once more:
0010 -> 0001
Step 5:
Shift the bits to the right one last time:
0001 -> 1000
Counting Sequence:
The counting sequence of the Johnson counter with an initial value of 1000 is as follows:
- 1000
- 0100
- 0010
- 0001
- 1000
Explanation of Options:
Let's analyze each option and determine if it matches the counting sequence of the Johnson counter.
Option A: 8, 12, 14, 7, 15, 3, 1, 0, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option B: 8, 0, 1, 3, 7, 15, 14, 12, 8
- This sequence matches the counting sequence of the Johnson counter.
Option C: 8, 10, 12, 14, 0, 2, 4, 6, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option D: 8, 12, 14, 15, 7, 3, 1, 0, 8
- This sequence matches the counting sequence of the Johnson counter.
Conclusion:
The counting sequence of the 4-bit Johnson counter with an initial value of 1000 is 8, 0, 1, 3, 7, 15, 14, 12, 8 (Option B) and 8, 12, 14, 15, 7, 3, 1, 0, 8 (Option D).
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Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?
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Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?.
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?.
Solutions for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?, a detailed solution for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? has been provided alongside types of Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
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