Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider a 4-bit Johnson counter with an init...
Start Learning for Free
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:
Note: MSB and LSB are not fixed for initial value.
- 8, 12, 14, 7, 15, 3, 1, 0, 8
- 8, 0, 1, 3, 7, 15, 14, 12, 8
- 8, 10, 12, 14, 0, 2, 4, 6, 8
- 8, 12, 14, 15, 7, 3, 1, 0, 8
- a)1
- b)2
- c)3
- d)4
Correct answer is option 'B,D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Consider a 4-bit Johnson counter with an initial value of 1000. The co...
Now,
Circuit for Johnson counter:
If Q0 is MSB and Q3 is LSB:
Count sequence of 8 → 12 → 14 → 15 → 7 → 3 → 1 → 0 → 8 → (repeat).
If Q3 is MSB and Q0 is LSB:
If Q3 is MSB and Q0 is LSB:
Count sequence of 8 → 0 → 1 → 3 → 7 → 15 → 14 → 12 → 8 → (repeat).
As we know,
Since the least significant bits and the most significant bit is not signified.
Hence, the correct options are (B) and (D).
Since the least significant bits and the most significant bit is not signified.
Hence, the correct options are (B) and (D).
Free Test
FREE
| Start Free Test |
Community Answer
Consider a 4-bit Johnson counter with an initial value of 1000. The co...
Introduction:
A Johnson counter is a modified version of a ring counter that generates a sequence of binary numbers. It is a shift register with feedback. In a 4-bit Johnson counter, there are four flip-flops connected in a ring, and the output of each flip-flop is connected to the input of the next flip-flop. The counting sequence of a Johnson counter depends on its initial value.
Given Information:
- A 4-bit Johnson counter
- Initial value: 1000
Counting Sequence:
To determine the counting sequence of the Johnson counter, we need to simulate the counter by manually shifting the values.
Step 1:
Start with the initial value: 1000
Step 2:
Shift the bits to the right, and the leftmost bit becomes the rightmost bit:
1000 -> 0100
Step 3:
Shift the bits to the right again:
0100 -> 0010
Step 4:
Shift the bits to the right once more:
0010 -> 0001
Step 5:
Shift the bits to the right one last time:
0001 -> 1000
Counting Sequence:
The counting sequence of the Johnson counter with an initial value of 1000 is as follows:
- 1000
- 0100
- 0010
- 0001
- 1000
Explanation of Options:
Let's analyze each option and determine if it matches the counting sequence of the Johnson counter.
Option A: 8, 12, 14, 7, 15, 3, 1, 0, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option B: 8, 0, 1, 3, 7, 15, 14, 12, 8
- This sequence matches the counting sequence of the Johnson counter.
Option C: 8, 10, 12, 14, 0, 2, 4, 6, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option D: 8, 12, 14, 15, 7, 3, 1, 0, 8
- This sequence matches the counting sequence of the Johnson counter.
Conclusion:
The counting sequence of the 4-bit Johnson counter with an initial value of 1000 is 8, 0, 1, 3, 7, 15, 14, 12, 8 (Option B) and 8, 12, 14, 15, 7, 3, 1, 0, 8 (Option D).
A Johnson counter is a modified version of a ring counter that generates a sequence of binary numbers. It is a shift register with feedback. In a 4-bit Johnson counter, there are four flip-flops connected in a ring, and the output of each flip-flop is connected to the input of the next flip-flop. The counting sequence of a Johnson counter depends on its initial value.
Given Information:
- A 4-bit Johnson counter
- Initial value: 1000
Counting Sequence:
To determine the counting sequence of the Johnson counter, we need to simulate the counter by manually shifting the values.
Step 1:
Start with the initial value: 1000
Step 2:
Shift the bits to the right, and the leftmost bit becomes the rightmost bit:
1000 -> 0100
Step 3:
Shift the bits to the right again:
0100 -> 0010
Step 4:
Shift the bits to the right once more:
0010 -> 0001
Step 5:
Shift the bits to the right one last time:
0001 -> 1000
Counting Sequence:
The counting sequence of the Johnson counter with an initial value of 1000 is as follows:
- 1000
- 0100
- 0010
- 0001
- 1000
Explanation of Options:
Let's analyze each option and determine if it matches the counting sequence of the Johnson counter.
Option A: 8, 12, 14, 7, 15, 3, 1, 0, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option B: 8, 0, 1, 3, 7, 15, 14, 12, 8
- This sequence matches the counting sequence of the Johnson counter.
Option C: 8, 10, 12, 14, 0, 2, 4, 6, 8
- This sequence does not match the counting sequence of the Johnson counter.
Option D: 8, 12, 14, 15, 7, 3, 1, 0, 8
- This sequence matches the counting sequence of the Johnson counter.
Conclusion:
The counting sequence of the 4-bit Johnson counter with an initial value of 1000 is 8, 0, 1, 3, 7, 15, 14, 12, 8 (Option B) and 8, 12, 14, 15, 7, 3, 1, 0, 8 (Option D).
Attention Computer Science Engineering (CSE) Students!
To make sure you are not studying endlessly, EduRev has designed Computer Science Engineering (CSE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Computer Science Engineering (CSE).
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Similar Computer Science Engineering (CSE) Doubts
Top Courses for Computer Science Engineering (CSE)View all
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?
Question Description
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?.
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?.
Solutions for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer?, a detailed solution for Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? has been provided alongside types of Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a 4-bit Johnson counter with an initial value of 1000. The counting sequence of this counter is/are:Note: MSB and LSB are not fixed for initial value. 8, 12, 14, 7, 15, 3, 1, 0, 8 8, 0, 1, 3, 7, 15, 14, 12, 8 8, 10, 12, 14, 0, 2, 4, 6, 8 8, 12, 14, 15, 7, 3, 1, 0, 8a)1b)2c)3d)4Correct answer is option 'B,D'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
|
|
Explore Courses for Computer Science Engineering (CSE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup