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What will be the measure of ∠BAE in the given figure with centre O, if AB and AE are tangents and CD is the diameter of the semicircle?
  • a)
    60°
  • b)
    80°
  • c)
    100°
  • d)
    120°
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
What will be the measure of ∠BAE in the given figure with centre O...
In △BEO,
∠BEO = ∠EBO = 30° [Because OE = OB]
∠BEO + ∠EBO + ∠EOB = 180°
⇒ 30° + 30° + ∠EOB = 180°
⇒ ∠EOB = 180° - 60°
⇒ ∠EOB = 120°
Also, ∠ABO = ∠AEO = 90° [Tangent is perpendicular to the radius of circle]
So, in quadrilateral ABOE,
∠ABO + ∠AEO + ∠EOB + ∠BAE = 360°
⇒ 90° + 90° + 120° + ∠BAE = 360°
⇒ ∠BAE = 360° - [90° + 90° + 120°]
⇒ ∠BAE = 360° - 300°
⇒ ∠BAE = 60°
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What will be the measure of ∠BAE in the given figure with centre O, if AB and AE are tangents and CD is the diameter of the semicircle?a)60°b)80°c)100°d)120°Correct answer is option 'A'. Can you explain this answer?
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