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A computer can execute 1000000 instructions per second. A program running on this computer performs, on an average, one sector read and one sector write for every 200 instructions that it executes. The disk drive handling the I/O transfers requires 0.00010 second each to perform the read and write operations. Assuming no overlap of these operations, the percentage of CPU time spent in the wait state is (Answer to the nearest integer)
    Correct answer is '91'. Can you explain this answer?
    Most Upvoted Answer
    A computer can execute 1000000 instructions per second. A program runn...
    Calculation of CPU time spent in the wait state:
    The percentage of CPU time spent in the wait state can be calculated by considering the time taken for I/O operations and the total time taken by the program to execute.

    Given data:
    - Instructions executed per second = 1000000
    - Average sector read/write per 200 instructions
    - Time taken for each read/write operation = 0.00010 seconds

    Calculations:
    1. Time taken for one sector read/write operation = 2 * 0.00010 = 0.00020 seconds
    2. Number of sector read/write operations per second = 1000000 / 200 = 5000
    3. Total time taken for all sector read/write operations per second = 5000 * 0.00020 = 1 second
    4. Percentage of CPU time spent in the wait state = (Time for I/O operations / Total time) * 100
    = (1 / 1) * 100
    = 100%

    Explanation:
    - The program spends 100% of the time waiting for I/O operations to complete, which means it is not utilizing the CPU during this time.
    - This leads to the CPU being idle for the entire duration of the I/O operations, resulting in a high percentage of CPU time spent in the wait state.
    Therefore, the correct answer is '100%', indicating that the CPU spends all its time waiting for I/O operations to complete.
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    Community Answer
    A computer can execute 1000000 instructions per second. A program runn...
    The wait time can be calculated in the following manner:
    Time to read one sector = 0.0010
    Time to write one sector = 0.0010
    Time to execute 200 instructions = 0.0002
    Total program cycle time = 0.0022
    Utilization time = 
    Wait time = 100 - 9 = 91%
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    A computer can execute 1000000 instructions per second. A program running on this computer performs, on an average, one sector read and one sector write for every 200 instructions that it executes. The disk drive handling the I/O transfers requires 0.00010 second each to perform the read and write operations. Assuming no overlap of these operations, the percentage of CPU time spent in the wait state is (Answer to the nearest integer)Correct answer is '91'. Can you explain this answer?
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    A computer can execute 1000000 instructions per second. A program running on this computer performs, on an average, one sector read and one sector write for every 200 instructions that it executes. The disk drive handling the I/O transfers requires 0.00010 second each to perform the read and write operations. Assuming no overlap of these operations, the percentage of CPU time spent in the wait state is (Answer to the nearest integer)Correct answer is '91'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about A computer can execute 1000000 instructions per second. A program running on this computer performs, on an average, one sector read and one sector write for every 200 instructions that it executes. The disk drive handling the I/O transfers requires 0.00010 second each to perform the read and write operations. Assuming no overlap of these operations, the percentage of CPU time spent in the wait state is (Answer to the nearest integer)Correct answer is '91'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A computer can execute 1000000 instructions per second. A program running on this computer performs, on an average, one sector read and one sector write for every 200 instructions that it executes. The disk drive handling the I/O transfers requires 0.00010 second each to perform the read and write operations. Assuming no overlap of these operations, the percentage of CPU time spent in the wait state is (Answer to the nearest integer)Correct answer is '91'. Can you explain this answer?.
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