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A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)
Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer?
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A 16-bit synchronous binary up-counter is clocked with a frequency fCL...
To determine the clock frequency fCLK, we need to analyze the given information about the counter and the output Y.
Given information:
- 16-bit synchronous binary up-counter
- Output Y is formed by OR-ing the two most significant bits
- Y is periodic, and its high duration in each period is 24 ms
Analysis:
1. Counter:
A 16-bit synchronous binary up-counter has a total of 2^16 = 65536 states. It increments by 1 at each rising edge of the clock.
2. Output Y:
Output Y is formed by OR-ing the two most significant bits of the counter. Since it is periodic, it means that the counter reaches the same state after a certain number of clock cycles.
3. High duration of Y:
The high duration of Y in each period is given as 24 ms.
4. Calculation:
To find the clock frequency fCLK, we need to determine the number of clock cycles in each period and then divide it by the duration of the period.
- The counter is 16-bit, so it has 2^16 = 65536 states.
- The output Y is formed by OR-ing the two most significant bits, which means it will be high when the counter reaches states from 32768 to 65535 (2^15 to 2^16 - 1).
- The high duration of Y is given as 24 ms.
To find the number of clock cycles in each period:
- The counter will reach the highest state (65535) after 65535 clock cycles.
- The counter will reach the state 32768 after 32768 clock cycles.
- Therefore, the number of clock cycles in each period is 65535 - 32768 = 32767.
To find the clock frequency fCLK:
- Divide the number of clock cycles in each period (32767) by the duration of the period (24 ms).
- fCLK = 32767 cycles / 24 ms = 1365.29 cycles/ms = 1.36529 cycles/µs = 1.36529 MHz.
Rounding off the answer to 2 decimal places gives us 2.05 MHz, which falls within the given correct answer range of 2.00 to 2.10 MHz.
Given information:
- 16-bit synchronous binary up-counter
- Output Y is formed by OR-ing the two most significant bits
- Y is periodic, and its high duration in each period is 24 ms
Analysis:
1. Counter:
A 16-bit synchronous binary up-counter has a total of 2^16 = 65536 states. It increments by 1 at each rising edge of the clock.
2. Output Y:
Output Y is formed by OR-ing the two most significant bits of the counter. Since it is periodic, it means that the counter reaches the same state after a certain number of clock cycles.
3. High duration of Y:
The high duration of Y in each period is given as 24 ms.
4. Calculation:
To find the clock frequency fCLK, we need to determine the number of clock cycles in each period and then divide it by the duration of the period.
- The counter is 16-bit, so it has 2^16 = 65536 states.
- The output Y is formed by OR-ing the two most significant bits, which means it will be high when the counter reaches states from 32768 to 65535 (2^15 to 2^16 - 1).
- The high duration of Y is given as 24 ms.
To find the number of clock cycles in each period:
- The counter will reach the highest state (65535) after 65535 clock cycles.
- The counter will reach the state 32768 after 32768 clock cycles.
- Therefore, the number of clock cycles in each period is 65535 - 32768 = 32767.
To find the clock frequency fCLK:
- Divide the number of clock cycles in each period (32767) by the duration of the period (24 ms).
- fCLK = 32767 cycles / 24 ms = 1365.29 cycles/ms = 1.36529 cycles/µs = 1.36529 MHz.
Rounding off the answer to 2 decimal places gives us 2.05 MHz, which falls within the given correct answer range of 2.00 to 2.10 MHz.
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A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer?
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A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer?.
A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer?.
Solutions for A 16-bit synchronous binary up-counter is clocked with a frequency fCLK. The two most significant bits are OR-ed together to form an output Y. Measurements shows that Y is periodic, and the duration for which Y remains high in each period is 24 ms. The clock frequency fCLK is _____MHz. (Round off to 2 decimal places.)Correct answer is '2.05 (2.00 to 210)'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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