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The population of a city in the first three continuous years is given as 6000, 8000 and 10000 respectively. What is the population of the city in the fourth continuous year, according to the geometric increase method?
  • a)
    11500
  • b)
    12000
  • c)
    12870
  • d)
    14000
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The population of a city in the first three continuous years is given ...
Given information:
Population in the first year = 6000
Population in the second year = 8000
Population in the third year = 10000

Geometric Increase Method:
In the geometric increase method, we use the formula:
Pn = P0 * (1 + r)^n
where
Pn = population in the nth year
P0 = initial population
r = rate of increase
n = number of years

To find the rate of increase, we can use the formula:
r = (P2 - P1) / P1
where
P1 = population in the first year
P2 = population in the second year

r = (8000 - 6000) / 6000
r = 0.3333

Using the above values in the formula for the fourth year, we get:
P4 = 6000 * (1 + 0.3333)^4
P4 = 12870

Therefore, the population of the city in the fourth continuous year, according to the geometric increase method, is 12870. Hence, the correct answer is option C.
Free Test
Community Answer
The population of a city in the first three continuous years is given ...
For geometric increase method,
Pn = P × (1+r)n
Where
Pn = Future Population, P = Latest known population and n = numbers of years


P4 = 10000 × (1 + 0.2885)1 = 12885
∴ The population of the city in the fourth continuous year will be 12885. 
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The population of a city in the first three continuous years is given as 6000, 8000 and 10000 respectively. What is the population of the city in the fourth continuous year, according to the geometric increase method?a)11500b)12000c)12870d)14000Correct answer is option 'C'. Can you explain this answer?
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