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In a circuit, there is a series connection of an ideal resistor and an ideal capacitor. The conduction current (in Amperes) through the resistor is . The displacement current (in Amperes) through the capacitor is
  • a)
    0
  • b)
    2 sin (t)
  • c)
    2sin (t +π)
  • d)
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a circuit, there is a series connection of an ideal resistor and a...
Given
Total current in capacitor, I = IC + ID
Where, outside capacitor plates we have only conduction current IC and no displacement current. On the other hand inside the capacitor there is no conduction current i.e. IC = 0 and there is only displacement current.
So, Iconduction = Idisplacement
∵ E = σ/ε0 [For the parallel plate capacitor]
ID = Iresistor
So, they will be in-phase, resistor and capacitor are in series so both current will be equal. Hence, the correct option is (D).
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Community Answer
In a circuit, there is a series connection of an ideal resistor and a...
Given
Total current in capacitor, I = IC + ID
Where, outside capacitor plates we have only conduction current IC and no displacement current. On the other hand inside the capacitor there is no conduction current i.e. IC = 0 and there is only displacement current.
So, Iconduction = Idisplacement
∵ E = σ/ε0 [For the parallel plate capacitor]
ID = Iresistor
So, they will be in-phase, resistor and capacitor are in series so both current will be equal. Hence, the correct option is (D).
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In a circuit, there is a series connection of an ideal resistor and an ideal capacitor. The conduction current (in Amperes) through the resistor is . The displacement current (in Amperes) through the capacitor isa)0b)2 sin (t)c)2sin (t +π)d)Correct answer is option 'D'. Can you explain this answer?
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