Consider the circuit shown in the figure with input V(t) in volts. Th...
Given circuit and the waveform of sinusoidal steady state current I(t) is shown below,
Method 1
From the waveform of current I(t) , the current is lagging with respect to supply voltage V(t), because at
t = 0, V(t) is 0 and t = π/4, I(t) is 0.
Hence, the circuit element Z is inductor.
Thus, Z = jXL
Peak value of current I(t) = 1/√2 A
Peak value of voltage V(t) = 1V
Therefore impedance of circuit,
Since, XL = ωL
ωL = 1
Here ω = 1 rad/sec
L = 1H
Hence, the correct option is (D).
Method 2
Using sinusoidal steady state analysis :
Given : V(t) = sint , ω = 1 rad/sec
The given waveform of current I(t) and voltage V(t) is shown below,
From above figure it is clear that current,
it shows I(t) lags from voltage V(t) by an angle of π/4 it mean given circuit offer lagging power factor that’s why Z must be inductive reactance.
Thus, Z = jωL so equation (i) becomes as,
If L = 1H, then and only then,
Hence, the correct option is (D).