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A solid sphere of radius 10 mm is placed at the centroid of a hollow cubical enclosure of side length 30 mm. The outer surface of the sphere is denoted by 1 and the inner surface of the cube is denoted by 2. The  view factor F22 for radiation heat transfer is _______ (round off to two decimal places). 
    Correct answer is '0.7641'. Can you explain this answer?
    Most Upvoted Answer
    A solid sphere of radius 10 mm is placed at the centroid of a hollow c...
    Given :
    R = 10 mm
    L = 30 mm
    Surface 1 is a convex surface (sphere) 
    So,  F11 = 0
    F11 + F12 = 1
    F12 = 1
    Apply reciprocal theorem, 
    Free Test
    Community Answer
    A solid sphere of radius 10 mm is placed at the centroid of a hollow c...
    Given data:


    • Radius of the solid sphere (r) = 10 mm

    • Side length of the hollow cubical enclosure (L) = 30 mm

    • Outer surface of the sphere denoted by 1

    • Inner surface of the cube denoted by 2



    Calculation:

    To calculate the view factor F22 for radiation heat transfer, we need to consider the geometry of the system.


    Step 1: Calculation of the surface areas

    The surface area of the sphere (A1) can be calculated using the formula:

    A1 = 4πr2

    Substituting the radius (r = 10 mm) into the formula, we get:

    A1 = 4π(102)

    A1 = 400π mm2


    The surface area of the cube (A2) can be calculated using the formula:

    A2 = 6L2

    Substituting the side length (L = 30 mm) into the formula, we get:

    A2 = 6(302)

    A2 = 5400 mm2


    Step 2: Calculation of the view factor

    The view factor F22 is defined as the fraction of radiation leaving surface 2 that strikes surface 2. In this case, surface 2 is the inner surface of the cube.

    The view factor can be calculated using the formula:

    F22 = A2/A1

    Substituting the values of A2 and A1 into the formula, we get:

    F22 = 5400/400π

    F22 ≈ 0.7641 (rounded to two decimal places)


    Final answer:

    The view factor F22 for radiation heat transfer is approximately 0.7641.
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    A solid sphere of radius 10 mm is placed at the centroid of a hollow cubical enclosure of side length 30 mm. The outer surface of the sphere is denoted by 1 and the inner surface of the cube is denoted by 2. The view factor F22 for radiation heat transfer is _______ (round off to two decimal places).Correct answer is '0.7641'. Can you explain this answer?
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    A solid sphere of radius 10 mm is placed at the centroid of a hollow cubical enclosure of side length 30 mm. The outer surface of the sphere is denoted by 1 and the inner surface of the cube is denoted by 2. The view factor F22 for radiation heat transfer is _______ (round off to two decimal places).Correct answer is '0.7641'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A solid sphere of radius 10 mm is placed at the centroid of a hollow cubical enclosure of side length 30 mm. The outer surface of the sphere is denoted by 1 and the inner surface of the cube is denoted by 2. The view factor F22 for radiation heat transfer is _______ (round off to two decimal places).Correct answer is '0.7641'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid sphere of radius 10 mm is placed at the centroid of a hollow cubical enclosure of side length 30 mm. The outer surface of the sphere is denoted by 1 and the inner surface of the cube is denoted by 2. The view factor F22 for radiation heat transfer is _______ (round off to two decimal places).Correct answer is '0.7641'. Can you explain this answer?.
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