Two RC coupled amplifiers are connected to form a 2-stage amplier. If...
Explanation:
To find the cutoff frequencies of the 2-stage amplifier, we need to consider the individual cutoff frequencies of each amplifier and analyze their combined effect.
Individual Amplifier Cutoff Frequencies:
The lower cutoff frequency, fL, of an RC coupled amplifier is given by the formula:
fL = 1 / (2πRC)
Given:
fL1 = 100 Hz
fL2 = 20 kHz
Combined Effect:
When two amplifiers are connected in series, the overall gain and bandwidth are determined by the product of the individual gains and bandwidths.
The overall gain, A, is given by:
A = A1 * A2
The overall bandwidth, B, is given by:
B = B1 * B2
The gain and bandwidth of each amplifier are related to their cutoff frequencies as follows:
A1 = 1 + (f / fL1)
A2 = 1 + (f / fL2)
B1 = fL1 / (A1 - 1)
B2 = fL2 / (A2 - 1)
Calculations:
To find the overall cutoff frequencies, we need to determine the frequencies at which the overall gain and bandwidth decrease by 3 dB (half power).
For the overall gain:
A = 1 + (f / fL1) * 1 + (f / fL2)
0.5A = 1 + (f / fL1) * 1 + (f / fL2)
Solving the above equation, we get:
f = (fL1 * fL2) / (sqrt(A) * (fL2 + fL1))
For the overall bandwidth:
B = fL1 / (A1 - 1) * fL2 / (A2 - 1)
0.5B = fL1 / (A1 - 1) * fL2 / (A2 - 1)
Solving the above equation, we get:
f = (fL1 * fL2) / (sqrt(B) * (fL2 + fL1))
Calculating the Cutoff Frequencies:
Substituting the given values:
fL1 = 100 Hz
fL2 = 20 kHz
For A = 0.5:
f = (100 * 20000) / (sqrt(0.5) * (20000 + 100))
f ≈ 12800 Hz
For B = 0.5:
f = (100 * 20000) / (sqrt(0.5) * (20000 + 100))
f ≈ 12800 Hz
Therefore, the cutoff frequencies of the 2-stage amplifier are approximately 12.8 kHz.
The correct answer is option 'B'.