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A 3300 V ,delta connected motor has a synchronous reactance per phase of 18 ohm. It operates at a leading power factor of 0.707 when drawing 800kW from the mains. Calculate its excitation e.m.f?
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A 3300 V ,delta connected motor has a synchronous reactance per phase ...
**Given:**
- Voltage (V) = 3300 V
- Connection = Delta
- Synchronous reactance per phase (Xs) = 18 Ω
- Power factor (pf) = 0.707 (leading)
- Power (P) = 800 kW

**To find:**
- Excitation e.m.f (E)

**Formula:**
- Power (P) = √3 * V * I * pf
- Where, I = current
- E = I * Xs

**Calculation:**
- √3 = 1.732
- I = P / (√3 * V * pf)
- I = 800000 / (1.732 * 3300 * 0.707)
- I = 186.93 A
- E = I * Xs
- E = 186.93 * 18
- E = 3364.74 V

**Answer:**
- Excitation e.m.f (E) = 3364.74 V

**Explanation:**
- The given motor is delta connected, which means the line voltage is equal to the phase voltage.
- The power factor is leading, which means the current leads the voltage.
- The power drawn by the motor is 800 kW, which means the total power drawn by the three phases is 2400 kW.
- Using the power formula, we can calculate the current drawn by the motor.
- Using the excitation formula, we can calculate the excitation e.m.f required for the motor to operate at the given power factor and power.
- Therefore, the excitation e.m.f of the motor is 3364.74 V.
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A 3300 V ,delta connected motor has a synchronous reactance per phase of 18 ohm. It operates at a leading power factor of 0.707 when drawing 800kW from the mains. Calculate its excitation e.m.f?
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