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There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared
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There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice CAT tests.