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There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?
  • a)
    2 kg, 1 kg
  • b)
    1 kg, 2 kg
  • c)
    3 kg, 2 kg
  • d)
    Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
There are two solutions of HCl in water. The first is 40% strong and t...
To solve this problem, we need to set up a system of equations based on the given information. Let's assume that the initial quantity of the 40% strong solution is x kg and the initial quantity of the 60% strong solution is y kg.

Given information:
1. When the two solutions are mixed with some amount of pure water, a 20% strong solution is obtained. This can be represented by the equation:
0.4x + 0.6y + 0 = 0.2(x + y)

2. If the same amount of an 80% strong solution had been added instead of pure water, a 70% strong solution would have been obtained. This can be represented by the equation:
0.4x + 0.6y + 0.8(x + y) = 0.7(x + y)

Now, let's solve these equations to find the values of x and y.

Solving equation 1:
0.4x + 0.6y = 0.2x + 0.2y
0.2x + 0.4y = 0
2x + 4y = 0

Solving equation 2:
0.4x + 0.6y + 0.8x + 0.8y = 0.7x + 0.7y
1.2x + 1.4y = 0.7x + 0.7y
0.5x + 0.7y = 0

Now, we have a system of equations:
2x + 4y = 0
0.5x + 0.7y = 0

Solving these equations, we find that x = 0 and y = 0. This means that the initial quantities of the 40% and 60% solutions are both 0 kg.

Hence, the initial quantity of the 40% and 60% solutions cannot be determined. Therefore, the correct answer is option D) Cannot be determined.
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There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer?
Question Description
There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are two solutions of HCl in water. The first is 40% strong and the second is 60% strong. The two solutions are mixed. Some amount of pure water is added and a 20% strong solution is obtained. If instead of adding pure water, the same amount of an 80% strong solution had been added to the mixture, then a 70% strong solution would have been obtained. What was the initial quantity of the 40% and the 60% solutions?a)2 kg, 1 kgb)1 kg, 2 kgc)3 kg, 2 kgd)Cannot be determinedCorrect answer is option 'D'. Can you explain this answer?.
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