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A compound C5H10O gives a positive test of carbonyl group, a negative test with Fehling solution, a positive haloform test and on reduction it gives normal pentane. Identify the compound.
- a)3 -Pentanone
- b)2 -Pentanone
- c)1, 5 -Pentanediol
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A compound C5H10O gives a positive test of carbonyl group, a negative...
1) The compound gives a positive test of the carbonyl group, i.e, it is either an aldehyde or a ketone.
2) It gives a negative test with Fehling solution. Hence, it cannot be an aldehyde.
3) A positive iodoform test is given by methyl ketone (−COCH3).
4) Also, 2-pentanone on reduction gives pentane.
Hence, it can be 2-pentanone (CH3−CO−CH2−CH2−CH3).
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A compound C5H10O gives a positive test of carbonyl group, a negative...
Compound Identification
Given Information:
- Compound: C5H10O
- Positive test for carbonyl group
- Negative test with Fehling solution
- Positive haloform test
- On reduction, it gives normal pentane
Test Results:
1. Positive test for carbonyl group:
- This indicates the presence of a carbonyl group (C=O) in the compound.
2. Negative test with Fehling solution:
- Fehling solution is used to test for the presence of aldehydes or reducing sugars.
- The negative test suggests that the compound does not contain an aldehyde group, as aldehydes are capable of reducing Fehling solution.
3. Positive haloform test:
- The haloform test is used to identify compounds with a methyl ketone (-COCH3) or a methyl carboxylic acid (-COOH) group.
- The positive test indicates the presence of a methyl ketone group in the compound.
4. On reduction, it gives normal pentane:
- Reduction of a carbonyl group can lead to the formation of an alcohol.
- The formation of normal pentane (C5H12) suggests that the compound contains a ketone group.
Compound Identification:
- Considering all the given information and test results, the compound can be identified as 2-pentanone (option B).
- The molecular formula of 2-pentanone is C5H10O, which matches the given information.
- 2-Pentanone contains a carbonyl group (C=O), as indicated by the positive test for the carbonyl group.
- It does not give a positive test with Fehling solution, suggesting the absence of an aldehyde group.
- The positive haloform test confirms the presence of a methyl ketone group in 2-pentanone.
- On reduction, 2-pentanone would yield normal pentane (C5H12), as described in the given information.
Therefore, the correct identification of the compound is 2-pentanone (option B).
Given Information:
- Compound: C5H10O
- Positive test for carbonyl group
- Negative test with Fehling solution
- Positive haloform test
- On reduction, it gives normal pentane
Test Results:
1. Positive test for carbonyl group:
- This indicates the presence of a carbonyl group (C=O) in the compound.
2. Negative test with Fehling solution:
- Fehling solution is used to test for the presence of aldehydes or reducing sugars.
- The negative test suggests that the compound does not contain an aldehyde group, as aldehydes are capable of reducing Fehling solution.
3. Positive haloform test:
- The haloform test is used to identify compounds with a methyl ketone (-COCH3) or a methyl carboxylic acid (-COOH) group.
- The positive test indicates the presence of a methyl ketone group in the compound.
4. On reduction, it gives normal pentane:
- Reduction of a carbonyl group can lead to the formation of an alcohol.
- The formation of normal pentane (C5H12) suggests that the compound contains a ketone group.
Compound Identification:
- Considering all the given information and test results, the compound can be identified as 2-pentanone (option B).
- The molecular formula of 2-pentanone is C5H10O, which matches the given information.
- 2-Pentanone contains a carbonyl group (C=O), as indicated by the positive test for the carbonyl group.
- It does not give a positive test with Fehling solution, suggesting the absence of an aldehyde group.
- The positive haloform test confirms the presence of a methyl ketone group in 2-pentanone.
- On reduction, 2-pentanone would yield normal pentane (C5H12), as described in the given information.
Therefore, the correct identification of the compound is 2-pentanone (option B).
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A compound C5H10O gives a positive test of carbonyl group, a negative test with Fehling solution, a positive haloform test and on reduction it gives normal pentane. Identify the compound.a)3 -Pentanoneb)2 -Pentanonec)1, 5 -Pentanediold)None of theseCorrect answer is option 'B'. Can you explain this answer?
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