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A sample of 3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid (in mg) adsorbed (per gram of charcoal) is (Nearest integer)
    Correct answer is '18'. Can you explain this answer?
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    A sample of 3 g of activated charcoal was added to 50 mL of acetic ac...
    Number of moles of acetic acid adsorbed
    ∴ Weight of acetic acid adsorbed = 0.9 × 60 mg
    = 54 mg
    Hence, the amount of acetic acid adsorbed per g of charcoal = 54/3 mg
    = 18 mg
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    A sample of 3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid (in mg) adsorbed (per gram of charcoal) is (Nearest integer)Correct answer is '18'. Can you explain this answer?
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    A sample of 3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid (in mg) adsorbed (per gram of charcoal) is (Nearest integer)Correct answer is '18'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A sample of 3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid (in mg) adsorbed (per gram of charcoal) is (Nearest integer)Correct answer is '18'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of 3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06 N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid (in mg) adsorbed (per gram of charcoal) is (Nearest integer)Correct answer is '18'. Can you explain this answer?.
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