Three consecutive integers add up to 51. What are these integers?Ans) ...
For ex:1,2 and 3 are consecutive integers.So if we take x as 1
x=1
To get 2 we have to add 1 to x
That means x+1
If we evaluate x as 1 we get 1+1=2
And the same goes to 3, x+2
Evaluating x as 1, 1+2=3
And the same applies to infinite integers
For ex:2+1=3,2+2=4
2,3 and 4 are integers
Now according to question asks three consecutive integers add up to 51.So from what I explained from the above, the consecutive integers are x,(x+1),(x+2).
So using algebra if we add the three consecutive integers it would be 51. So
x+(x+1)+(x+2)=51
Removing brackets : x+x+1+x+2 = 51
=3x+3 =51
=3x+3-3 =51-3 (balancing equation by subtracting both sides by 3)
=3x =48
=3x/3 =48/3 (balancing equation by dividing both sides by 3)
=x =16
So we got x =16
Now if we evaluate x as 16 then x=16, x+1 =16+1=17, x+2 =16+2=18.
If we add 16,17 and 18 we get 16+17+18 = 51
Therefore, the integers are 16,17 and 18.