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A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed?
Most Upvoted Answer
A contract on construction job specifies a penalty for delay of comple...
Understanding the Penalty Structure
The penalty for delay in completion of the construction job increases with each passing day. The structure is as follows:
- Rs. 200 for the 1st day
- Rs. 250 for the 2nd day
- Rs. 300 for the 3rd day
- Rs. 350 for the 4th day
- And so on...
This penalty increases by Rs. 50 for each successive day.
Finding the Total Penalty Paid
The total penalty paid by the contractor is Rs. 27,750. We can express the penalty for each day mathematically. The penalty for the nth day can be represented as:
- Penalty on day n = Rs. (200 + 50(n - 1))
To find the total penalty for 'd' days, we need to sum the penalties from day 1 to day d.
Calculating the Total Payment
The total penalty can be calculated using the sum formula for arithmetic series:
- Total penalty = (Number of days) / 2 x (First term + Last term)
Where:
- First term (day 1) = Rs. 200
- Last term (day d) = Rs. (200 + 50(d - 1))
Thus,
- Total penalty = d/2 x (200 + (200 + 50(d - 1)))
Setting this equal to Rs. 27,750, we can simplify and solve for 'd'.
Solving the Equation
From the equation:
- 27,750 = d/2 x (400 + 50(d - 1))
This simplifies to:
- 27,750 = d/2 x (50d + 350)
By multiplying through by 2 and rearranging terms, we can find the value of 'd'.
Final Calculation
After performing the necessary calculations, we find that:
- The number of days delayed (d) = 30 days
Thus, the construction work was delayed for 30 days, resulting in a total penalty of Rs. 27,750.
The penalty for delay in completion of the construction job increases with each passing day. The structure is as follows:
- Rs. 200 for the 1st day
- Rs. 250 for the 2nd day
- Rs. 300 for the 3rd day
- Rs. 350 for the 4th day
- And so on...
This penalty increases by Rs. 50 for each successive day.
Finding the Total Penalty Paid
The total penalty paid by the contractor is Rs. 27,750. We can express the penalty for each day mathematically. The penalty for the nth day can be represented as:
- Penalty on day n = Rs. (200 + 50(n - 1))
To find the total penalty for 'd' days, we need to sum the penalties from day 1 to day d.
Calculating the Total Payment
The total penalty can be calculated using the sum formula for arithmetic series:
- Total penalty = (Number of days) / 2 x (First term + Last term)
Where:
- First term (day 1) = Rs. 200
- Last term (day d) = Rs. (200 + 50(d - 1))
Thus,
- Total penalty = d/2 x (200 + (200 + 50(d - 1)))
Setting this equal to Rs. 27,750, we can simplify and solve for 'd'.
Solving the Equation
From the equation:
- 27,750 = d/2 x (400 + 50(d - 1))
This simplifies to:
- 27,750 = d/2 x (50d + 350)
By multiplying through by 2 and rearranging terms, we can find the value of 'd'.
Final Calculation
After performing the necessary calculations, we find that:
- The number of days delayed (d) = 30 days
Thus, the construction work was delayed for 30 days, resulting in a total penalty of Rs. 27,750.
Community Answer
A contract on construction job specifies a penalty for delay of comple...
Sn=n/2[2a+(n-1) d 27750=n/2[2*200+(n-1)50 Solve it answer will come 30 days
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A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed?
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A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed?.
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows rs.200 for 1st day rs.250 for second day we.300 for third day and so on if the contractor pays rs. 27750 as penalty find the no. of days for which the construction work is delayed?.
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