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Consider array has n elements and searching element X. What is the minimum and the maximum number of comparisons are required to search a element?
Note: Searching is successful.
- a)0,n
- b)0,n-1
- c)1,n
- d)1,n-1
Correct answer is option 'C'. Can you explain this answer?
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Consider array has n elements and searching element X. What is the min...
Concept:
Linear search:
A linear search, often known as a sequential search, is a technique for locating an element in a list. It systematically verifies each element of the list until a match is discovered or the entire list has been searched.
Linear search:
A linear search, often known as a sequential search, is a technique for locating an element in a list. It systematically verifies each element of the list until a match is discovered or the entire list has been searched.
Algorithm:
linear_search(int a[], int n, int X)
{
for (int i = 0; i < n; i++)
{
if (a[i] == X)
return i+1;
}
linear_search(int a[], int n, int X)
{
for (int i = 0; i < n; i++)
{
if (a[i] == X)
return i+1;
}
}
Explanation:
The given data,
An array has n elements and searching element X.
The minimum number of comparisons:
Consider an array is a[5] ={ 12, 5, 48, 79, 11}
X=12
The X element is compared with a[0] and returns the search is successful.
So the minimum number of comparisons is= 1.
The maximum number of comparisons:
Consider an array is a[5] ={ 12, 5, 48, 79, 11}
X=11
The X element is compared with a[0] and not found,and it compares each index element of array i.e a[1], a[2], a[3], a[4].
Then the X element is found at a[4] and returns the search is successful.
So the minimum number of comparisons is= n.
Hence the correct answer is 1,n.
The given data,
An array has n elements and searching element X.
The minimum number of comparisons:
Consider an array is a[5] ={ 12, 5, 48, 79, 11}
X=12
The X element is compared with a[0] and returns the search is successful.
So the minimum number of comparisons is= 1.
The maximum number of comparisons:
Consider an array is a[5] ={ 12, 5, 48, 79, 11}
X=11
The X element is compared with a[0] and not found,and it compares each index element of array i.e a[1], a[2], a[3], a[4].
Then the X element is found at a[4] and returns the search is successful.
So the minimum number of comparisons is= n.
Hence the correct answer is 1,n.
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Consider array has n elements and searching element X. What is the minimum and the maximum number of comparisons are required to search a element?Note: Searching is successful.a)0,nb)0,n-1c)1,nd)1,n-1Correct answer is option 'C'. Can you explain this answer?
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