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Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what?
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Iqbal treated a lustrous, divalent element M with sodium hydroxide. He...
Observations:
- Bubbles were formed when the element M was treated with sodium hydroxide and hydrochloric acid.
Explanation:
When a lustrous, divalent element M reacts with both sodium hydroxide and hydrochloric acid, the formation of bubbles indicates the release of a gas. The gas produced in this reaction is hydrogen gas (H2).
Reaction with Sodium Hydroxide:
The reaction between element M and sodium hydroxide can be represented as follows:
M + 2NaOH → Na2M + H2O
In this reaction, the element M displaces hydrogen from sodium hydroxide, resulting in the formation of sodium M and water. The release of hydrogen gas leads to the formation of bubbles.
Reaction with Hydrochloric Acid:
The reaction between element M and hydrochloric acid can be represented as follows:
M + 2HCl → MCl2 + H2
In this reaction, the element M displaces hydrogen from hydrochloric acid, forming the chloride salt of M and releasing hydrogen gas as a byproduct. The evolution of hydrogen gas causes the formation of bubbles in the reaction mixture.
Identification of the Gas:
The gas produced in both reactions is hydrogen gas (H2). This can be confirmed by performing a simple test for hydrogen gas. For example, if a lighted splint is brought near the bubbles, it will cause a "pop" sound as the hydrogen gas ignites.
Conclusion:
When the divalent element M reacts with sodium hydroxide or hydrochloric acid, bubbles are observed due to the release of hydrogen gas. The formation of bubbles is an indication of the chemical reaction taking place and the evolution of a gas.
- Bubbles were formed when the element M was treated with sodium hydroxide and hydrochloric acid.
Explanation:
When a lustrous, divalent element M reacts with both sodium hydroxide and hydrochloric acid, the formation of bubbles indicates the release of a gas. The gas produced in this reaction is hydrogen gas (H2).
Reaction with Sodium Hydroxide:
The reaction between element M and sodium hydroxide can be represented as follows:
M + 2NaOH → Na2M + H2O
In this reaction, the element M displaces hydrogen from sodium hydroxide, resulting in the formation of sodium M and water. The release of hydrogen gas leads to the formation of bubbles.
Reaction with Hydrochloric Acid:
The reaction between element M and hydrochloric acid can be represented as follows:
M + 2HCl → MCl2 + H2
In this reaction, the element M displaces hydrogen from hydrochloric acid, forming the chloride salt of M and releasing hydrogen gas as a byproduct. The evolution of hydrogen gas causes the formation of bubbles in the reaction mixture.
Identification of the Gas:
The gas produced in both reactions is hydrogen gas (H2). This can be confirmed by performing a simple test for hydrogen gas. For example, if a lighted splint is brought near the bubbles, it will cause a "pop" sound as the hydrogen gas ignites.
Conclusion:
When the divalent element M reacts with sodium hydroxide or hydrochloric acid, bubbles are observed due to the release of hydrogen gas. The formation of bubbles is an indication of the chemical reaction taking place and the evolution of a gas.
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Iqbal treated a lustrous, divalent element M with sodium hydroxide. He...
Hudrogen and the element is zinc
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Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what?
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Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what?.
Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid. He find that the produced gas is what?.
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