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A positive edge-triggered D flip-flop is connected to a positive edge-triggered J K flip-flop. The Q output of the D flip-flop is connected to both the J and K inputs of the J K flip-flop, while the Q output of the J K flip-flop is connected to the input of the D flip-flop. At first, the output of a D flip-flop is set to logic one, and the output of the JK flip-flop is cleared. Which one of the following options is the bit sequence generated at the Q output of the JK flip-flop when the flip-flops are connected to a free-running standard clock? Consider that J = K = 1 is the toggle mode and J = K = 0 is the state-holding mode of the JK flip-flop. Both the flip-flops have non-zero propagation delays.
  • a)
    0 1 1 0 1 1 0
  • b)
    0 1 0 0 1 0 0
  • c)
    0 1 1 1 0 1 1 1 0 
  • d)
    0 1 1 0 0 1 1 0 0
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A positive edge-triggered D flip-flop is connected to a positive edge-...
At first, the Q output of D - FF = 1 in starting Q output of J K - F F = 0. Now with the help of the present state and next state, the circuit.
  • Toggle: J = K = 1
  • Hold : J = K = 0
Make table Q output of D-FF is going to next state input of J K-F F and the bits sequence produced is like 110110…..Including initial condition (0), we get output as 0110110110. Hence answer is (A) part.
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Community Answer
A positive edge-triggered D flip-flop is connected to a positive edge-...


Explanation:

Initial State:
- Initially, the D flip-flop output is set to logic one, and the JK flip-flop output is cleared.

Operation:
- When the clock signal triggers the D flip-flop, its output (Q) will be fed to both the J and K inputs of the JK flip-flop.
- Based on the J = K = 1 toggle mode of the JK flip-flop, the output will toggle between 0 and 1.
- The toggling of the JK flip-flop output will then be fed back to the D flip-flop.
- This feedback loop will cause the JK flip-flop to keep toggling its output state.

Sequence Generation:
- Initially, the D flip-flop output is 1, causing the JK flip-flop to toggle its output to 1.
- The JK flip-flop output of 1 is then fed back to the D flip-flop, causing it to change its output to 0.
- This feedback loop will continue, generating the sequence 0 1 1 0 1 1 0 at the Q output of the JK flip-flop.

Therefore, the bit sequence generated at the Q output of the JK flip-flop when connected to a free-running standard clock is 0 1 1 0 1 1 0.
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A positive edge-triggered D flip-flop is connected to a positive edge-triggered J K flip-flop. The Q output of the D flip-flop is connected to both the J and K inputs of the J K flip-flop, while the Q output of the J K flip-flop is connected to the input of the D flip-flop. At first, the output of a D flip-flop is set to logic one, and the output of the JK flip-flop is cleared. Which one of the following options is the bit sequence generated at the Q output of the JK flip-flop when the flip-flops are connected to a free-running standard clock? Consider that J = K = 1 is the toggle mode and J = K = 0 is the state-holding mode of the JK flip-flop. Both the flip-flops have non-zero propagation delays.a)0 1 1 0 1 1 0b)0 1 0 0 1 0 0c)0 1 1 1 0 1 1 1 0d)0 1 1 0 0 1 1 0 0Correct answer is option 'A'. Can you explain this answer?
Question Description
A positive edge-triggered D flip-flop is connected to a positive edge-triggered J K flip-flop. The Q output of the D flip-flop is connected to both the J and K inputs of the J K flip-flop, while the Q output of the J K flip-flop is connected to the input of the D flip-flop. At first, the output of a D flip-flop is set to logic one, and the output of the JK flip-flop is cleared. Which one of the following options is the bit sequence generated at the Q output of the JK flip-flop when the flip-flops are connected to a free-running standard clock? Consider that J = K = 1 is the toggle mode and J = K = 0 is the state-holding mode of the JK flip-flop. Both the flip-flops have non-zero propagation delays.a)0 1 1 0 1 1 0b)0 1 0 0 1 0 0c)0 1 1 1 0 1 1 1 0d)0 1 1 0 0 1 1 0 0Correct answer is option 'A'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about A positive edge-triggered D flip-flop is connected to a positive edge-triggered J K flip-flop. The Q output of the D flip-flop is connected to both the J and K inputs of the J K flip-flop, while the Q output of the J K flip-flop is connected to the input of the D flip-flop. At first, the output of a D flip-flop is set to logic one, and the output of the JK flip-flop is cleared. Which one of the following options is the bit sequence generated at the Q output of the JK flip-flop when the flip-flops are connected to a free-running standard clock? Consider that J = K = 1 is the toggle mode and J = K = 0 is the state-holding mode of the JK flip-flop. Both the flip-flops have non-zero propagation delays.a)0 1 1 0 1 1 0b)0 1 0 0 1 0 0c)0 1 1 1 0 1 1 1 0d)0 1 1 0 0 1 1 0 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A positive edge-triggered D flip-flop is connected to a positive edge-triggered J K flip-flop. The Q output of the D flip-flop is connected to both the J and K inputs of the J K flip-flop, while the Q output of the J K flip-flop is connected to the input of the D flip-flop. At first, the output of a D flip-flop is set to logic one, and the output of the JK flip-flop is cleared. Which one of the following options is the bit sequence generated at the Q output of the JK flip-flop when the flip-flops are connected to a free-running standard clock? Consider that J = K = 1 is the toggle mode and J = K = 0 is the state-holding mode of the JK flip-flop. Both the flip-flops have non-zero propagation delays.a)0 1 1 0 1 1 0b)0 1 0 0 1 0 0c)0 1 1 1 0 1 1 1 0d)0 1 1 0 0 1 1 0 0Correct answer is option 'A'. Can you explain this answer?.
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