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A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound is
- a)primary alcohol
- b)tertiary alcohol
- c)alkene
- d)ether
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A compound is soluble in conc. HSO, it does not decolourise bromine in...
Answer:
The given compound is soluble in conc. H2SO4, does not decolourise bromine in carbon tetrachloride and is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. Based on these observations, the original compound is a primary alcohol.
Explanation:
Solubility in Conc. H2SO4:
The given compound is soluble in conc. H2SO4, which indicates that it is an organic compound. Among the given options, primary alcohols are soluble in conc. H2SO4 due to the formation of alkyl hydrogen sulphates.
Decolourisation of Bromine in Carbon Tetrachloride:
The given compound does not decolourise bromine in carbon tetrachloride, which indicates that it is not an alkene or a tertiary alcohol. Alkenes and tertiary alcohols can decolourise bromine in carbon tetrachloride due to the addition of bromine molecule across the double bond or through the formation of an alkyl bromide.
Oxidation by Chromic Anhydride in Aqueous Sulphuric Acid:
The given compound is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. This observation is consistent with the oxidation of a primary alcohol to an aldehyde and then to a carboxylic acid. The blue-green colour is due to the formation of Cr3+ ions, while the opacity is due to the formation of insoluble Cr(OH)3.
Conclusion:
Based on the above observations, the given compound is a primary alcohol, which can be oxidised by chromic anhydride in aqueous sulphuric acid to form carboxylic acid.
The given compound is soluble in conc. H2SO4, does not decolourise bromine in carbon tetrachloride and is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. Based on these observations, the original compound is a primary alcohol.
Explanation:
Solubility in Conc. H2SO4:
The given compound is soluble in conc. H2SO4, which indicates that it is an organic compound. Among the given options, primary alcohols are soluble in conc. H2SO4 due to the formation of alkyl hydrogen sulphates.
Decolourisation of Bromine in Carbon Tetrachloride:
The given compound does not decolourise bromine in carbon tetrachloride, which indicates that it is not an alkene or a tertiary alcohol. Alkenes and tertiary alcohols can decolourise bromine in carbon tetrachloride due to the addition of bromine molecule across the double bond or through the formation of an alkyl bromide.
Oxidation by Chromic Anhydride in Aqueous Sulphuric Acid:
The given compound is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. This observation is consistent with the oxidation of a primary alcohol to an aldehyde and then to a carboxylic acid. The blue-green colour is due to the formation of Cr3+ ions, while the opacity is due to the formation of insoluble Cr(OH)3.
Conclusion:
Based on the above observations, the given compound is a primary alcohol, which can be oxidised by chromic anhydride in aqueous sulphuric acid to form carboxylic acid.
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Community Answer
A compound is soluble in conc. HSO, it does not decolourise bromine in...
Explanation:
- Solubility in conc. H₂SO₄: This characteristic suggests that the compound is likely to be a primary alcohol. Primary alcohols are soluble in concentrated sulfuric acid due to the formation of alkyl hydrogen sulfates.
- Does not decolourise bromine in carbon tetrachloride: This rules out the possibility of the compound being a double bond or an alkene, as alkenes typically decolourise bromine in carbon tetrachloride due to addition reactions.
- Oxidised by chromic anhydride in aqueous sulphuric acid: The rapid oxidation of the compound by chromic anhydride in aqueous sulfuric acid to form a blue, green, and then opaque solution indicates that the compound is a primary alcohol. Primary alcohols are easily oxidized by chromic anhydride to form carboxylic acids, resulting in the color changes observed.
Therefore, based on the given characteristics, the original compound is most likely a primary alcohol.
- Solubility in conc. H₂SO₄: This characteristic suggests that the compound is likely to be a primary alcohol. Primary alcohols are soluble in concentrated sulfuric acid due to the formation of alkyl hydrogen sulfates.
- Does not decolourise bromine in carbon tetrachloride: This rules out the possibility of the compound being a double bond or an alkene, as alkenes typically decolourise bromine in carbon tetrachloride due to addition reactions.
- Oxidised by chromic anhydride in aqueous sulphuric acid: The rapid oxidation of the compound by chromic anhydride in aqueous sulfuric acid to form a blue, green, and then opaque solution indicates that the compound is a primary alcohol. Primary alcohols are easily oxidized by chromic anhydride to form carboxylic acids, resulting in the color changes observed.
Therefore, based on the given characteristics, the original compound is most likely a primary alcohol.
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A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer?
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A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer?.
A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound is soluble in conc. HSO, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isa)primary alcoholb)tertiary alcoholc)alkened)etherCorrect answer is option 'A'. Can you explain this answer?.
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