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Alkaline earth metals are denser than alkali metals because metallic bonding in alkaline earth's metal is
  • a)
    weaker.
  • b)
    stronger.
  • c)
    volatile.
  • d)
    not present.
Correct answer is option 'B'. Can you explain this answer?
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Alkaline earth metals are denser than alkali metals because metallic b...
Explanation:

Atomic Structure:
Alkaline earth metals have two valence electrons in their outermost shell which is one of the reasons for their high reactivity. Alkali metals also have one valence electron in their outermost shell and are highly reactive.

Metallic Bonding:
Alkaline earth metals have stronger metallic bonding when compared to alkali metals. This is because the two valence electrons in the outermost shell of alkaline earth metals are tightly held by the positively charged nucleus. The two electrons are also closer to the nucleus when compared to alkali metals which have only one valence electron.

Density:
Density is defined as the mass per unit volume of a substance. Alkaline earth metals have higher atomic masses when compared to alkali metals. This is because alkaline earth metals have two more protons in their nucleus when compared to alkali metals. This means that the atomic radius of alkaline earth metals is smaller than alkali metals.

When these metals come together to form a crystal lattice, the smaller atomic radius of alkaline earth metals makes the lattice more compact. This results in a higher packing density when compared to alkali metals. This is why alkaline earth metals are denser than alkali metals.

Conclusion:
Alkaline earth metals have stronger metallic bonding when compared to alkali metals. This, combined with a smaller atomic radius, results in a higher packing density and hence, a higher density overall.
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Alkaline earth metals are denser than alkali metals because metallic b...
Alkaline earth metals (ns2) are regraded as denser than alkali metal (ns1) because metallic bonding in alkaline earth metal is stronger.
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A system of greater disorder of molecules is more probable. The disorder of molecules is reflected by the entropy of the system. A liquid vaporizes to form a more disordered gas. When a solulte is present , there is additional contribution to the entropy of the liquid due to increase randomness. As the entropy of solution is higher than that of pure liquid, there is weaker tendency to form the gas.Thus , a solute (non volatil e) lowers the vapour pressure of a liquid, and hence a higher booing point of the solution Similarly, the greater randomness of the solution opposes the tendency to freeze. In consequence, a lower the temperature must be reached for achieving the equilibrium between the solid (frozen solvent) and the solution . Elevation of B.Pt. Tband depression of F.Pt. Tfof a solution are the colligative properties which depend only on the concentration of particles of the solute, not their identity.For dilute solutions, Tband Tfare proportional to the molality of the solute in the solution.The vaues of Kb and Kf do depend on the properties of the solvent. For liquids, is almost constant . [Troutans Rule , this constant for most of the Unassociated liquids (not having any strong bonding like Hydrogen bonding in the liquid state) is equal to 90J/mol. ] For solutes undergoing change of molecular state is solution (ionization or association), the observed T values differ from the calculate ones using the above relations. In such situations, the relationships are modified as Where i = Vant Hoff factor, greater than unity for ionization and smaller than unity for association of the solute molecules.Q.A mixture of two immiscible liquids at a constant pressure of 1 atm boils at a temperature

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Alkaline earth metals are denser than alkali metals because metallic bonding in alkaline earths metal isa)weaker.b)stronger.c)volatile.d)not present.Correct answer is option 'B'. Can you explain this answer?
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