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The sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time is
- a)432
- b)108
- c)36
- d)18
Correct answer is option 'B'. Can you explain this answer?
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Solution:
We need to find the sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time.
Let us consider the units place digits of all the numbers formed with the help of these digits.
The units place digits of the numbers formed with the help of 3,4,5,6 are as follows:
3, 4, 5, 6, 3, 4, 5, 6, 3, 4, 5, 6, 3, 4, 5, 6
Therefore, the sum of the units place digits of all the numbers formed with the help of 3,4,5,6 taken all at a time is:
3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 = 8(3 + 4 + 5 + 6) = 8 × 18 = 144
Since we are interested in the sum of the digits in the unit place, we need to find the sum of the digits in 4 numbers.
The possible digits in the units place are 3, 4, 5, and 6.
Therefore, the sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time is:
4 × (3 + 4 + 5 + 6) = 4 × 18 = 72
Hence, the correct answer is option B, 108.
We need to find the sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time.
Let us consider the units place digits of all the numbers formed with the help of these digits.
The units place digits of the numbers formed with the help of 3,4,5,6 are as follows:
3, 4, 5, 6, 3, 4, 5, 6, 3, 4, 5, 6, 3, 4, 5, 6
Therefore, the sum of the units place digits of all the numbers formed with the help of 3,4,5,6 taken all at a time is:
3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 + 3 + 4 + 5 + 6 = 8(3 + 4 + 5 + 6) = 8 × 18 = 144
Since we are interested in the sum of the digits in the unit place, we need to find the sum of the digits in 4 numbers.
The possible digits in the units place are 3, 4, 5, and 6.
Therefore, the sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time is:
4 × (3 + 4 + 5 + 6) = 4 × 18 = 72
Hence, the correct answer is option B, 108.
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The sum of the digits in the unit place of all the numbers formed with the help of 3,4,5,6 taken all at a time isa)432b)108c)36d)18Correct answer is option 'B'. Can you explain this answer?
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