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What is the quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?
  • a)
    270 and 1.00
  • b)
    290 and 1.04
  • c)
    290 and 1.00
  • d)
    312 and 1.04
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What is the quantity of cement (in kg) and of dry sand (in cubic meter...
Concept:
The following is parameters and properties of cement:
1. Bulk density of cement = 1440 kg/m3
2. Specific gravity of cement = 3.15
3. Weight of one bag of cement = 50 kg
4. Volume of cement bag = 50/1440 = 0.035 m3
5. Number of cement bags in 1 m3 = 30 approx.
6. Volume of dry mortar is 30% more than the volume of wet mortar.
∴ The volume of dry mortar = 1.3 × volume of wet mortar
Calculation:
1 m3 of wet cement mortar will correspond to 1.25 m3 of dry mortar
Sum of proportions = 1 + 5 = 6
Cement = 1.3/6 = 0.216m3
1 m3 of cement = 1440 kg
So, 0.216 m3 to cement = 312 kg
Sand = (5 x 1.3)/6 = 1.08m3
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Community Answer
What is the quantity of cement (in kg) and of dry sand (in cubic meter...
Calculation of Quantity of Cement:
- The proportion of cement in the cement mortar is given as 1:5.
- This means that for every 1 part of cement, we need 5 parts of sand.
- Let the quantity of cement be represented by 'x' kg.
- Since the total proportion is 1+5=6, the total quantity of cement and sand combined will be 6 parts.
- Hence, the quantity of sand will be 5 parts out of the total 6 parts.
- Therefore, the quantity of sand will be (5/6) cubic meter.

Calculation of Quantity of Sand:
- The quantity of sand required is given by the total quantity (1 cubic meter) minus the quantity of cement.
- Therefore, the quantity of sand will be (1 - x) cubic meter.

Equation:
- From the above calculations, we have determined the quantity of cement as 'x' kg and the quantity of sand as (1 - x) cubic meter.
- The weight of 1 cubic meter of cement is 1440 kg.
- The weight of cement is directly proportional to its volume. Therefore, we can write the equation as:
x/1440 = (1 - x)/1
- Simplifying the equation, we get:
x = 1440(1 - x)
x = 1440 - 1440x
1441x = 1440
x = 1440/1441
x ≈ 0.9986 kg

Final Answer:
- The quantity of cement required is approximately 0.9986 kg.
- The quantity of sand required is approximately (1 - 0.9986) = 0.0014 cubic meter.
- Therefore, the correct answer is option 'D': 312 kg of cement and 1.04 cubic meter of dry sand are required to prepare 1 cubic meter of wet cement mortar in a proportion of 1:5.
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What is the quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?a)270 and 1.00b)290 and 1.04c)290 and 1.00d)312 and 1.04Correct answer is option 'D'. Can you explain this answer?
Question Description
What is the quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?a)270 and 1.00b)290 and 1.04c)290 and 1.00d)312 and 1.04Correct answer is option 'D'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?a)270 and 1.00b)290 and 1.04c)290 and 1.00d)312 and 1.04Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?a)270 and 1.00b)290 and 1.04c)290 and 1.00d)312 and 1.04Correct answer is option 'D'. Can you explain this answer?.
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