The taxi fare in a city for first km is ₹8 and for subsequent distance...
Linear Equation for Taxi Fare
In a city, the taxi fare for the first km is ₹8 and for subsequent distance, it is ₹5 per km. Let the distance covered by the taxi be x km and the taxi fare be y.
Calculating the Fare
For the first km, the fare will be ₹8. For the subsequent distance, the fare will be ₹5 per km. Therefore, the fare for (x-1) km will be ₹5(x-1) = ₹5x - ₹5.
So, the total fare y for x km distance can be calculated as:
y = ₹8 + ₹5x - ₹5
Simplifying the equation, we get:
y = ₹5x + ₹3
Interpretation of the Equation
The above equation y = ₹5x + ₹3 represents the linear relationship between the distance covered by the taxi and the fare charged. The slope of the line is 5, which means that for every additional km, the fare increases by ₹5. The y-intercept of the line is 3, which represents the fixed cost of ₹3 that is charged irrespective of the distance covered.
Using this equation, we can calculate the fare for any distance covered by the taxi.
Example
Suppose the distance covered by the taxi is 10 km. Then, the fare charged will be:
y = ₹5(10) + ₹3 = ₹53
Therefore, the fare charged for a 10 km journey will be ₹53.