Find the roots of the following (a) 2x square+5/3x-2=0 (b) 3underoot 2x square - 5x-underoot 2=0?

Question

Answer

(a)2x^2+5/3x-2=02x^2/2+(5/3x)/2-2/2=0x^2+5/6x-1=0x^2+5/6x=1x^2+5/6x+(5/12)^2=1+(5/12)^2(x+5/12)^2=1+25/144(x+5/12)^2=(144+25)/144(x+5/12)^2=169/144x+5/12=+_13/12x=5/12+13/12, x=5/12-13/12x=18/12, x=-8/12x=3/2, x=-4/3(b) 3√2x^2-5x-√2=03√2x^2-6x+x-√2=0(3√2x^2-6x)+(x-√2)=03√2x(x-√2)+1(x-√2)=0(x-√2)(3√2x+1)=0x=√2, x=-1/3√2

Answer

3

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