The age of Nirmal is 30% less than that of his brother’s age. Rishu, ...
Given information:
- The age of Nirmal is 30% less than that of his brother's age.
- Rishu, who is Nirmal's cousin, is 5/2 years older than Nirmal.
- Rishu's father's age is 200% more than Rishu's age.
- The sum of ages of all of them except Nirmal's brother is 60 years.
To find:
The age of Nirmal.
Assumptions:
- Let's assume Nirmal's brother's age is B years.
- Nirmal's age will be 30% less than B, so his age will be B - 0.3B = 0.7B years.
Calculations:
Let's calculate the ages step by step:
1. Rishu's age:
- Rishu's age = Nirmal's age + 5/2 years (as Rishu is 5/2 years older than Nirmal)
2. Rishu's father's age:
- Rishu's father's age = Rishu's age + 200% of Rishu's age (as Rishu's father's age is 200% more than Rishu's age)
- Rishu's father's age = Rishu's age + 2 * Rishu's age = 3 * Rishu's age
3. Sum of ages:
- Sum of ages of Nirmal, Rishu, and Rishu's father = Nirmal's age + Rishu's age + Rishu's father's age
Given that the sum of ages of all of them except Nirmal's brother is 60 years, we can write the equation as:
Nirmal's age + Rishu's age + Rishu's father's age = 60
Now, let's substitute the values we obtained earlier:
0.7B + (0.7B + 5/2) + 3 * (0.7B + 5/2) = 60
Simplifying the equation:
0.7B + 0.7B + 5/2 + 3 * 0.7B + 3 * 5/2 = 60
2.8B + 5/2 + 10.5B + 15/2 = 60
13.3B + 10 = 60
13.3B = 50
B = 50/13.3
Now, we can substitute the value of B in Nirmal's age equation:
Nirmal's age = 0.7 * (50/13.3)
Nirmal's age ≈ 10 years
Therefore, the age of Nirmal is approximately 10 years.