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A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c = 3.0 x 108 ms-1]
- a)219.3 m
- b)219.2 m
- c)2192 m
- d)21.92 cm
Correct answer is option 'A'. Can you explain this answer?
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A particular station of All India Radio, New Delhi, broadcasts on a fr...
Calculating the Wavelength:
To calculate the wavelength of the electromagnetic radiation emitted by the transmitter, we can use the formula:
\[ \text{Wavelength} = \frac{Speed\ of\ Light}{Frequency} \]
Given:
Speed of Light, \( c = 3.0 \times 10^8 \, ms^{-1} \)
Frequency, \( f = 1368 \, kHz = 1368 \times 10^3 \, Hz \)
Plugging in the Values:
Substitute the values into the formula:
\[ \text{Wavelength} = \frac{3.0 \times 10^8 \, ms^{-1}}{1368 \times 10^3 \, Hz} \]
\[ \text{Wavelength} = \frac{3.0 \times 10^8}{1368 \times 10^3} \, m \]
\[ \text{Wavelength} = \frac{3.0}{1368} \times 10^5 \, m \]
\[ \text{Wavelength} = 2.193 \times 10^2 \, m \]
Converting meters to millimeters gives us:
\[ \text{Wavelength} = 219.3 \, mm \]
Therefore, the wavelength of the electromagnetic radiation emitted by the transmitter is 219.3 mm. Hence, option A (219.3 m) is the correct answer.
To calculate the wavelength of the electromagnetic radiation emitted by the transmitter, we can use the formula:
\[ \text{Wavelength} = \frac{Speed\ of\ Light}{Frequency} \]
Given:
Speed of Light, \( c = 3.0 \times 10^8 \, ms^{-1} \)
Frequency, \( f = 1368 \, kHz = 1368 \times 10^3 \, Hz \)
Plugging in the Values:
Substitute the values into the formula:
\[ \text{Wavelength} = \frac{3.0 \times 10^8 \, ms^{-1}}{1368 \times 10^3 \, Hz} \]
\[ \text{Wavelength} = \frac{3.0 \times 10^8}{1368 \times 10^3} \, m \]
\[ \text{Wavelength} = \frac{3.0}{1368} \times 10^5 \, m \]
\[ \text{Wavelength} = 2.193 \times 10^2 \, m \]
Converting meters to millimeters gives us:
\[ \text{Wavelength} = 219.3 \, mm \]
Therefore, the wavelength of the electromagnetic radiation emitted by the transmitter is 219.3 mm. Hence, option A (219.3 m) is the correct answer.
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A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c = 3.0 x 108 ms-1]a)219.3 mb)219.2 mc)2192 md)21.92 cmCorrect answer is option 'A'. Can you explain this answer?
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A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c = 3.0 x 108 ms-1]a)219.3 mb)219.2 mc)2192 md)21.92 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c = 3.0 x 108 ms-1]a)219.3 mb)219.2 mc)2192 md)21.92 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particular station of All India Radio, New Delhi, broadcasts on a frequency of 1,368kHz (kilohertz). The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light, c = 3.0 x 108 ms-1]a)219.3 mb)219.2 mc)2192 md)21.92 cmCorrect answer is option 'A'. Can you explain this answer?.
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