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a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time
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a train starting from rest moves with a uniform acceleration of 0.2m/s...
**Calculating the Speed Acquired**
To calculate the speed acquired by the train, we can use the formula:
v = u + at
Where:
- v is the final velocity
- u is the initial velocity (which is 0 m/s as the train starts from rest)
- a is the acceleration (0.2 m/s^2)
- t is the time (5 minutes)
Since the given time is in minutes, we need to convert it to seconds as the unit of acceleration is in m/s^2. There are 60 seconds in a minute, so 5 minutes is equal to 5 * 60 = 300 seconds.
Now, substituting the values into the formula:
v = 0 + (0.2 * 300)
v = 0 + 60
v = 60 m/s
Therefore, the speed acquired by the train in 5 minutes is 60 m/s.
**Calculating the Distance Travelled**
To calculate the distance travelled by the train, we can use the formula:
s = ut + (1/2)at^2
Where:
- s is the distance travelled
- u is the initial velocity (0 m/s)
- a is the acceleration (0.2 m/s^2)
- t is the time (300 seconds)
Substituting the values into the formula:
s = 0 * 300 + (1/2) * 0.2 * (300)^2
s = 0 + 0.1 * 90000
s = 0 + 9000
s = 9000 meters
Therefore, the distance travelled by the train in 5 minutes is 9000 meters.
**Explanation**
The given problem states that a train starts from rest, meaning its initial velocity is 0 m/s. The train then accelerates uniformly at a rate of 0.2 m/s^2 for a total time of 5 minutes.
To determine the speed acquired by the train, we use the formula v = u + at, where the initial velocity (u) is 0 m/s, the acceleration (a) is 0.2 m/s^2, and the time (t) is 5 minutes (which is converted to 300 seconds). By substituting these values into the formula, we find that the speed acquired by the train is 60 m/s.
To calculate the distance travelled by the train, we use the formula s = ut + (1/2)at^2. Again, the initial velocity (u) is 0 m/s, the acceleration (a) is 0.2 m/s^2, and the time (t) is 300 seconds. By substituting these values into the formula, we find that the distance travelled by the train is 9000 meters.
In summary, the train acquires a speed of 60 m/s and travels a distance of 9000 meters in 5 minutes.
To calculate the speed acquired by the train, we can use the formula:
v = u + at
Where:
- v is the final velocity
- u is the initial velocity (which is 0 m/s as the train starts from rest)
- a is the acceleration (0.2 m/s^2)
- t is the time (5 minutes)
Since the given time is in minutes, we need to convert it to seconds as the unit of acceleration is in m/s^2. There are 60 seconds in a minute, so 5 minutes is equal to 5 * 60 = 300 seconds.
Now, substituting the values into the formula:
v = 0 + (0.2 * 300)
v = 0 + 60
v = 60 m/s
Therefore, the speed acquired by the train in 5 minutes is 60 m/s.
**Calculating the Distance Travelled**
To calculate the distance travelled by the train, we can use the formula:
s = ut + (1/2)at^2
Where:
- s is the distance travelled
- u is the initial velocity (0 m/s)
- a is the acceleration (0.2 m/s^2)
- t is the time (300 seconds)
Substituting the values into the formula:
s = 0 * 300 + (1/2) * 0.2 * (300)^2
s = 0 + 0.1 * 90000
s = 0 + 9000
s = 9000 meters
Therefore, the distance travelled by the train in 5 minutes is 9000 meters.
**Explanation**
The given problem states that a train starts from rest, meaning its initial velocity is 0 m/s. The train then accelerates uniformly at a rate of 0.2 m/s^2 for a total time of 5 minutes.
To determine the speed acquired by the train, we use the formula v = u + at, where the initial velocity (u) is 0 m/s, the acceleration (a) is 0.2 m/s^2, and the time (t) is 5 minutes (which is converted to 300 seconds). By substituting these values into the formula, we find that the speed acquired by the train is 60 m/s.
To calculate the distance travelled by the train, we use the formula s = ut + (1/2)at^2. Again, the initial velocity (u) is 0 m/s, the acceleration (a) is 0.2 m/s^2, and the time (t) is 300 seconds. By substituting these values into the formula, we find that the distance travelled by the train is 9000 meters.
In summary, the train acquires a speed of 60 m/s and travels a distance of 9000 meters in 5 minutes.
Community Answer
a train starting from rest moves with a uniform acceleration of 0.2m/s...
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a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time
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a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time.
a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for a train starting from rest moves with a uniform acceleration of 0.2m/s sq for 5 min . calculate the speed acquired and the distance travelled in this time.
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