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If alpha and beta are zero of polynomial x^2+6x+k such that alpha-beta=2 find the value of k?
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If alpha and beta are zero of polynomial x^2+6x+k such that alpha-bet...
**Problem:**
Find the value of 'k' in the polynomial equation x^2 + 6x + k = 0, given that the difference between its zeroes is 2.

**Solution:**

We are given a quadratic polynomial equation x^2 + 6x + k = 0 and we need to find the value of 'k' when the difference between its zeroes is 2.

Let's solve this problem step by step:

**Step 1: Understand the question**
We need to find the value of 'k' when the difference between the zeroes of the given quadratic equation is 2.

**Step 2: Recall the concept of zeroes of a quadratic equation**
The zeroes of a quadratic equation ax^2 + bx + c = 0 are the values of 'x' at which the equation equals zero. In other words, they are the values of 'x' that satisfy the equation.

**Step 3: Understand the relationship between the zeroes and coefficients**
For a quadratic equation ax^2 + bx + c = 0, the sum of the zeroes is given by the formula:
Sum of zeroes (α + β) = -b/a
The product of the zeroes is given by the formula:
Product of zeroes (α * β) = c/a

**Step 4: Use the given information to form equations**
We are given that the difference between the zeroes (α - β) is 2. Using this information, we can form the equation:
α - β = 2

**Step 5: Form equations using the relationship between zeroes and coefficients**
We can use the relationship between the zeroes and coefficients to form two more equations.
From the given equation, we can identify that a = 1, b = 6, and c = k.
Using the formulas mentioned in Step 3, we can form the following equations:
α + β = -b/a = -6/1 = -6
α * β = c/a = k/1 = k

**Step 6: Solve the equations**
We now have a system of three equations:
α - β = 2
α + β = -6
α * β = k

We can solve this system of equations using various methods like substitution, elimination, or graphing. Let's solve it using the elimination method.

Adding the first two equations, we get:
(α - β) + (α + β) = 2 + (-6)
2α = -4
α = -2

Now, substituting the value of α in the second equation, we get:
-2 + β = -6
β = -6 + 2
β = -4

**Step 7: Find the value of 'k'**
Finally, we need to find the value of 'k'. We can substitute the values of α and β in the equation α * β = k to get:
-2 * (-4) = k
8 = k

Therefore, the value of 'k' is 8.

**Step 8: Verify the solution**
To verify our solution, we can substitute the values of α, β, and k in the given quadratic equation and check if it satisfies the equation.
Substituting α = -2, β = -4, and k = 8 in the equation x^2 + 6x + k = 0, we get:
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If alpha and beta are zero of polynomial x^2+6x+k such that alpha-beta=2 find the value of k?
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If alpha and beta are zero of polynomial x^2+6x+k such that alpha-beta=2 find the value of k? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about If alpha and beta are zero of polynomial x^2+6x+k such that alpha-beta=2 find the value of k? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If alpha and beta are zero of polynomial x^2+6x+k such that alpha-beta=2 find the value of k?.
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