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If there were 10 periods in the periodic table then how many elements would this period can maximum comprise of. (a) 50 (b) 72 (c) 32 (d) 98?
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If there were 10 periods in the periodic table then how many elements ...
Introduction:
The periodic table is a tabular arrangement of chemical elements, organized based on their atomic number, electron configuration, and recurring chemical properties. It consists of groups (vertical columns) and periods (horizontal rows). As of now, there are 7 periods in the periodic table, with a maximum of 7 elements in each period.

Explanation:
If there were 10 periods in the periodic table, we need to determine the maximum number of elements that can be accommodated in this hypothetical scenario.

1. Current Periodic Table:
As mentioned earlier, the current periodic table consists of 7 periods. The first period (Period 1) has only 2 elements (Hydrogen and Helium), while the second and third periods have 8 elements each. From the fourth period onwards, each period can accommodate a maximum of 18 elements. This pattern continues until the seventh period.

2. Maximum Elements in Each Period:
To determine the maximum number of elements in each period, we need to analyze the pattern. From the fourth period onwards, there is an addition of one new subshell (energy level) in each period. Each subshell can accommodate a maximum of 2n^2 electrons, where 'n' represents the principal quantum number of the subshell.

For example:
- Fourth period (n=4) has subshells 4s, 3d, and 4p, accommodating a total of 2(4^2) = 32 electrons.
- Fifth period (n=5) has subshells 5s, 4d, and 5p, accommodating a total of 2(5^2) = 50 electrons.
- Sixth period (n=6) has subshells 6s, 4f, 5d, and 6p, accommodating a total of 2(6^2) = 72 electrons.
- Seventh period (n=7) has subshells 7s, 5f, 6d, and 7p, accommodating a total of 2(7^2) = 98 electrons.

3. Maximum Elements in 10th Period:
Following the pattern observed in the current periodic table, if there were 10 periods, we can calculate the maximum number of elements in the 10th period using the above method.

- Tenth period (n=10) would have subshells 10s, 6f, 7d, 8p, 9f, 10d, and 10p.
- The 6f subshell can accommodate a maximum of 2(6^2) = 72 electrons.
- The 7d subshell can accommodate a maximum of 2(7^2) = 98 electrons.
- The 8p subshell can accommodate a maximum of 2(8^2) = 128 electrons.
- The 9f subshell can accommodate a maximum of 2(9^2) = 162 electrons.
- The 10d subshell can accommodate a maximum of 2(10^2) = 200 electrons.
- The 10p subshell can accommodate a maximum of 2(10^2) = 200 electrons.

Adding up all these maximum electron
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If there were 10 periods in the periodic table then how many elements would this period can maximum comprise of. (a) 50 (b) 72 (c) 32 (d) 98?
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