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Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2?
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Which of the following sets of quantum number is correct for an electr...
Answer:
The correct set of quantum numbers for an electron in the 4f orbital is (c) n = 4, l = 3, m = 1, s = 1/2.
Let's break down the quantum numbers and explain why this is the correct set.
1. Principal Quantum Number (n):
The principal quantum number represents the energy level of an electron. It can have positive integer values starting from 1. In this case, n = 4, which means the electron is in the fourth energy level.
2. Azimuthal Quantum Number (l):
The azimuthal quantum number determines the shape of the orbital. It can have values ranging from 0 to (n-1). In this case, l = 3, which means the electron is in the f orbital. The f orbital has a complex shape with 7 suborbitals.
3. Magnetic Quantum Number (m):
The magnetic quantum number specifies the orientation of the orbital in space. It can have values ranging from -l to +l. In this case, m = 1, which means the electron is in the f orbital and specifically in one of the suborbitals.
4. Spin Quantum Number (s):
The spin quantum number represents the spin of the electron. It can have two possible values: +1/2 (spin-up) or -1/2 (spin-down). In this case, s = 1/2, which means the electron has a spin-up configuration.
Explanation:
Now let's analyze each of the given options and determine if they are correct or not.
(a) n = 4, l = 3, m = 4, s = 1/2:
- The value of m cannot be greater than l. In this case, m = 4 is greater than l = 3, so this option is incorrect.
(b) n = 4, l = 4, m = –4, s = –1/2:
- The value of l cannot be greater than or equal to n. In this case, l = 4 is equal to n = 4, so this option is incorrect.
(c) n = 4, l = 3, m = 1, s = 1/2:
- This set of quantum numbers satisfies all the rules and corresponds to the correct 4f orbital. Therefore, this option is correct.
(d) n = 3, l = 2, m = –2, s = 1/2:
- The value of m cannot be negative or equal to l. In this case, m = -2 is negative and equal to l = 2, so this option is incorrect.
In conclusion, the correct set of quantum numbers for an electron in the 4f orbital is (c) n = 4, l = 3, m = 1, s = 1/2.
The correct set of quantum numbers for an electron in the 4f orbital is (c) n = 4, l = 3, m = 1, s = 1/2.
Let's break down the quantum numbers and explain why this is the correct set.
1. Principal Quantum Number (n):
The principal quantum number represents the energy level of an electron. It can have positive integer values starting from 1. In this case, n = 4, which means the electron is in the fourth energy level.
2. Azimuthal Quantum Number (l):
The azimuthal quantum number determines the shape of the orbital. It can have values ranging from 0 to (n-1). In this case, l = 3, which means the electron is in the f orbital. The f orbital has a complex shape with 7 suborbitals.
3. Magnetic Quantum Number (m):
The magnetic quantum number specifies the orientation of the orbital in space. It can have values ranging from -l to +l. In this case, m = 1, which means the electron is in the f orbital and specifically in one of the suborbitals.
4. Spin Quantum Number (s):
The spin quantum number represents the spin of the electron. It can have two possible values: +1/2 (spin-up) or -1/2 (spin-down). In this case, s = 1/2, which means the electron has a spin-up configuration.
Explanation:
Now let's analyze each of the given options and determine if they are correct or not.
(a) n = 4, l = 3, m = 4, s = 1/2:
- The value of m cannot be greater than l. In this case, m = 4 is greater than l = 3, so this option is incorrect.
(b) n = 4, l = 4, m = –4, s = –1/2:
- The value of l cannot be greater than or equal to n. In this case, l = 4 is equal to n = 4, so this option is incorrect.
(c) n = 4, l = 3, m = 1, s = 1/2:
- This set of quantum numbers satisfies all the rules and corresponds to the correct 4f orbital. Therefore, this option is correct.
(d) n = 3, l = 2, m = –2, s = 1/2:
- The value of m cannot be negative or equal to l. In this case, m = -2 is negative and equal to l = 2, so this option is incorrect.
In conclusion, the correct set of quantum numbers for an electron in the 4f orbital is (c) n = 4, l = 3, m = 1, s = 1/2.
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Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2?
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Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2?.
Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following sets of quantum number is correct for an electron in 4f-orbital (a) n = 4, l = 3, m = 4, s = 1/2 (b) n = 4, l = 4, m = –4, s = –1/2 (c) n = 4, l = 3, m = 1, s = 1/2 (d) n = 3, l = 2, m = –2, s = 1/2?.
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