The number of group homomorphism from the group Z4 to the group S3 is?
Number of Group Homomorphisms from Z4 to S3
Introduction:
In group theory, a group homomorphism is a map between two groups that preserves the group structure. We are given the groups Z4 and S3, and we need to determine the number of group homomorphisms from Z4 to S3.
Definition of Z4 and S3:
Z4 is the group of integers modulo 4 under addition. It consists of the elements {0, 1, 2, 3}, where addition is performed modulo 4. S3 is the symmetric group on 3 elements. It consists of all possible permutations of the elements {1, 2, 3}.
Properties of Group Homomorphisms:
To determine the number of group homomorphisms from Z4 to S3, we need to consider the properties of group homomorphisms:
1. Homomorphism preserves the identity: The identity element in Z4 is 0, and the identity element in S3 is the identity permutation. Therefore, any group homomorphism from Z4 to S3 must map 0 to the identity permutation in S3.
2. Homomorphism preserves inverses: For any element x in Z4, its inverse is -x (modulo 4). Similarly, for any permutation σ in S3, its inverse is denoted by σ^(-1). A group homomorphism from Z4 to S3 must preserve inverses, i.e., it must satisfy f(-x) = f(x)^(-1) for all x in Z4.
3. Homomorphism preserves group operation: The group operation in Z4 is addition modulo 4, while the group operation in S3 is composition of permutations. A group homomorphism from Z4 to S3 must preserve the group operation, i.e., it must satisfy f(x + y) = f(x) ◦ f(y) for all x, y in Z4.
Number of Group Homomorphisms:
Given the above properties, we can determine the number of group homomorphisms from Z4 to S3 as follows:
1. Mapping of 0: Since the identity element 0 in Z4 must be mapped to the identity permutation in S3, there is only one possibility for this mapping.
2. Mapping of other elements: Let's consider an element x in Z4 (excluding 0). The possible images of x in S3 are the permutations that satisfy the above properties. Since S3 has 6 elements, we need to count the number of permutations that satisfy these properties.
3. Conclusion: The number of group homomorphisms from Z4 to S3 is equal to the number of permutations in S3 that satisfy the above properties. This number can be computed by considering the possible mappings for each element in Z4 (excluding 0) to the elements in S3.
Summary:
To summarize, the number of group homomorphisms from Z4 to S3 can be determined by considering the properties of group homomorphisms and counting the possible mappings for each element in Z4 (excluding 0) to the elements in S3.
The number of group homomorphism from the group Z4 to the group S3 is?
Group Homomorphism
Group homomorphism is a function between two groups that preserves the group operation. In other words, it maps the product of two elements in one group to the product of their images in the other group. If we have two groups G and H, a group homomorphism from G to H is denoted as φ:G→H, and it satisfies the property φ(a⋅b) = φ(a)⋅φ(b) for all elements a, b in G.
Number of Group Homomorphisms from Z4 to S3
To determine the number of group homomorphisms from the group Z4 to the group S3, we need to consider the properties and structures of both groups.
Group Z4
The group Z4 is the cyclic group of integers modulo 4, which consists of the elements {0, 1, 2, 3}. The group operation is addition modulo 4. It is important to note that Z4 is an abelian group.
Group S3
The group S3 is the symmetric group on three elements, which consists of all possible permutations of three objects. It has a total of 6 elements, which can be represented as {e, (12), (13), (23), (123), (132)}. The group operation is composition of permutations.
Mapping Elements
In order for a function φ:Z4→S3 to be a group homomorphism, it must satisfy the property φ(a⋅b) = φ(a)⋅φ(b) for all elements a, b in Z4.
Trivial Homomorphism
The trivial homomorphism is the homomorphism that maps every element of the domain group to the identity element of the codomain group. In this case, the trivial homomorphism maps all elements in Z4 to the identity permutation (e) in S3. This is a valid group homomorphism.
Non-Trivial Homomorphism
For a non-trivial homomorphism to exist, the generator of Z4 must be mapped to an element in S3 with the same order. Since Z4 is cyclic and the order of the generator 1 is 4, the element φ(1) in S3 must also have an order of 4.
Number of Non-Trivial Homomorphisms
The number of non-trivial homomorphisms from Z4 to S3 is equal to the number of elements in S3 that have an order of 4. By examining the elements in S3, we can see that there are no elements with an order of 4. Therefore, there are no non-trivial homomorphisms from Z4 to S3.
Conclusion
In summary, there is exactly one group homomorphism from Z4 to S3, which is the trivial homomorphism that maps all elements in Z4 to the identity element in S3. There are no non-trivial homomorphisms from Z4 to S3.